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Korvikt [17]
3 years ago
13

True or False:

Physics
2 answers:
kondaur [170]3 years ago
8 0
I know the answer is true
bekas [8.4K]3 years ago
5 0
I think it false. Sorry if i'm wrong.

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Which of the following is a business product?
worty [1.4K]

Answer:

A

Explanation:

3 0
3 years ago
What is decay constant?​
Sloan [31]
The size of atoms is the answer
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3 years ago
A basketball player has made 60​% of his foul shots during the season. Assuming the shots are​ independent, find the probability
marissa [1.9K]

Answer:

a) 0.0864

b) 0.0384

c) 0.936

Explanation:

Probability that he makes his shot, P(A) = 0.6

Probability that he doesn't make the shot, P(A') = 1 - P(A) = 1 - 0.6 = 0.4

a) Probability that he Misses for the first time on his fourth attempt

P(A) × P(A) × P(A) × P(A') = 0.6 × 0.6 × 0.6 × 0.4 = 0.0864

b) Probability that he Makes his first basket on his fourth shot

P(A') × P(A') × P(A') × P(A) = 0.4 × 0.4 × 0.4 × 0.6 = 0.0384

c) Probability that he Makes his first basket on one of his first 3 shots

Sum of the probabilities that he makes all three first shots, two of the first three shots and one of the first three shots with the order irrelevant.

- Probability that he makes all first three shots = P(A) × P(A) × P(A) = 0.6 × 0.6 × 0.6 = 0.216

- Probability that he makes two out of the first three shots = (P(A) × P(A) × P(A')) + (P(A) × P(A') × P(A)) + (P(A') × P(A) × P(A)) = 3(0.6 × 0.6 × 0.4) = 0.432 (it's multipled by 3 because the probability is the same regardless of order)

- Probability of making only one of the first three shots = (P(A) × P(A') × P(A')) + (P(A') × P(A) × P(A')) + (P(A') × P(A') × P(A)) = 3(0.6 × 0.4 × 0.4) = 0.288 (It's multiplied by 3 too because the probabilities are the same too, regardless of order).

Probability that he Makes his first basket on one of his first 3 shots = 0.216 + 0.432 + 0.288 = 0.936

5 0
3 years ago
A sandbag motionless in outer space is hit by a three-times-as massive sandbag moving at 12 m/s. They stick together. This is an
vekshin1

Answer:

This is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

Explanation:

Let the mass of the motionless sandbag = m₁

Let the mass of the moving sandbag = m₂ = 3m₁

initial velocity of the motionless sandbag, u₁ = 0

initial velocity of the moving sandbag, u₂ = 12 m/s

Let their final velocity, = v

Collision between two particles can either be elastic or inelastic.

Since they stick together after the impact, then the collision is inelastic

Apply the principle of conservation of linear momentum;

Initial kinetic energy = final kinetic energy

¹/₂m₁u₁² + ¹/₂m₂u₂² = ¹/₂v²(m₁ + m₂)

¹/₂m₁(0)² + ¹/₂(3m₁)(12)² = ¹/₂v²(m₁+3m₁)

216m₁ = 2m₁ v²

v² = 108

v = √108

v = 10.392 m/s

Change in kinetic energy = Final kinetic energy - initial kinetic energy

Initial Kinetic energy, KE₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

                                   KE₁ = ¹/₂m₁(0)² + ¹/₂(3m₁)(12)²

                                   KE₁ = 216m₁ J

Final kinetic energy, KE₂ = ¹/₂v²(m₁ + m₂)

                                  KE₂ = ¹/₂(108)(m₁ + 3m₁)

                                  KE₂ = 216m₁ J

ΔKE = KE₂ - KE₁ =  216m₁ J -  216m₁ J = 0%

Therefore, this is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

4 0
3 years ago
Who discovered natural magnet for the first time?​
andrew-mc [135]
Answer: Magnes



Explanation: Magnes found that the nails and buckle of his sandals and the tip of his staff were attracted to the rock he was standing on. He dug up the Earth to find lodestones. Lodestones contain magnetite, a natural magnetic material Fe3O4.
8 0
3 years ago
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