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Akimi4 [234]
3 years ago
5

What is a risky behaviour​

Physics
2 answers:
Sindrei [870]3 years ago
7 0

Explanation:

Doing homework is risky behaviour broo

mel-nik [20]3 years ago
7 0
Taking credit of someone else’s work.
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The chemical equation provided shows iron rusting to form iron oxide. Use the drop-down menu to choose the coefficients that wil
Brrunno [24]

Answer:

4 Fe + 3 O_2 \rightarrow 2 Fe_2 O_3

Explanation:

The original equation is:

Fe + O_2 \rightarrow Fe_2 O_3

We notice that:

- we have 1 atom of Fe on the left, and 2 atoms of Fe on the right

- we have 2 atoms of O on the left, and 3 atoms of O on the right

Therefore, the equation is not balanced.

In order to balance it, we can add:

- a coefficient 3 in front of O_2

- a coefficient 2 in front of Fe_2 O_3

So we have:

Fe + 3 O_2 \rightarrow 2Fe_2O_3

Now the oxygen is balanced, but the iron it not balanced yet, since we have 1 Fe on the left and 4 on the right. Therefore, we should add a coefficient 4 on the Fe on the left:

4 Fe + 3 O_2 \rightarrow 2 Fe_2 O_3

3 0
3 years ago
Read 2 more answers
Approximately _____ of those who suffer from anorexia nervosa literally starve themselves to death.
Vadim26 [7]
Appproximately 10% of those who suffer from anorexia nervosa literally starve themselves to death.
6 0
3 years ago
How to solve arctan[tan(7pi /4)] ...?
Svet_ta [14]
Well, 
arctan is a bijection from R into (-pi/2 , pi/2)*and 
pi is a period of tangent function: 
so 
as we have : tan(7pi/4) = tan(pi - pi/4) = - tan(pi/4) 
we finally get : 

<span>arctan(tan(7pi/4)) = artan(tan(- pi/4)) = - pi/4 
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
7 0
3 years ago
Tarzan (75 kg) swings from 4 metres high on a vine down to ground level and catches Jane (50 kg). How fast are they moving after
Kruka [31]

Try this solution (if it is possible, check it in other sources):

1. for m_Tarzan=75kg., initial_height=4m., end_height=0 m. and g=10 N/kg. Energy is:

E=m_{Tarzan}*(H_{initial}-H_{end})*g=75*4*10=3000(J).

2. The same value of Energy is applied for m_Tarzan+Jane=75+50=125 kg.:

E=\frac{m_{Tarzan+Jane}* Speed^2}{2}; \ => \ Speed=\sqrt{ \frac{2*E}{m_{Tarzan+Jane}}};

3. According to the formula of the Speed:

Speed=sqrt(6000/125)=sqrt(48)=4sqrt(3)≈4*1.71=6.84 (m/s)


Answer: 6.84 (m. per sec.)

5 0
3 years ago
how much horse power is needed to move a box that has a force of 1,492 newtons a distance of 2 meters in 1 second
stellarik [79]

This one is a piece 'o cake if you know the definition
of a horsepower, and impossible if you don't.

It is:            1 horsepower = 746 watts

Also, remember that  1 watt = 1 joule/second
                
Now:            Work = (force) x (distance)

To move this box 2 meters,

                     Work = (1,492 newtons) x (2 meters) = 2,984 joules

If you accomplished that feat in 1 second,
then you produced power of

                               (2,984 / 1) (joule/second) = 2,984 watts . 

                             (2,984 watt) x (1 HP / 746 watt) = 4 horsepower .

That's the solution, applying bullet-proof math and physics to the
given data.  But in the real world, I guarantee that you didn't do that.
______________________________________

By the way ... a comment regarding the terminology in the question:

The box doesn't "have a force" of 1,492 newtons.  That's the force
with which you ... or a horse, or an ox ... pushed against the box
in order to move it.

(And, if I might observe, that force is about 336 pounds,
so my money would be on the horse or the ox.)
5 0
3 years ago
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