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zepelin [54]
2 years ago
10

A bungee jumper starts with 1000 J in their GPE store. After they jump they fall and are brought to a stop with the bungee cord.

With the cord fully stretched what is the energy in the EPE store?
Physics
1 answer:
pochemuha2 years ago
8 0

Answer:

energy is equal to 1000 J

Explanation:

When the jumper is in the tent, he has a given height, this height gives him a gravitational potential energy, which forms his initial mechanical energy of 1000 J. After jumping, this energy is converted into elastic energy of the rope plus a remainder of potential energy gravitational, it does not reach the ground, but as the friction is negligible the total mechanical energy is conserved, therefore its energy is equal to 1000 J

This is a case of energy transformation, but the total value of mechanical energy does not change

         

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A horse of mass 242 kg pulls a cart of mass 224 kg. The acceleration of gravity is 9.8 m/s 2 . What is the largest acceleration
Rufina [12.5K]

To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

Where,

m= Mass

a = Acceleration

At the same time the frictional force can be defined as,

F_f = \mu N

Where,

\mu = Frictional coefficient

N = Normal force (mass*gravity)

Our values are given as,

m_h = 242 kg\\m_c = 224 kg\\\mu = 0.894\\

By condition of Balance the friction force must be equal to the total net force, that is to say

F_{net} = F_f

m_{total}a = \mu m_hg

(m_h+m_c)a = \mu*m_h*g

Re-arrange to find acceleration,

a= \frac{\mu*m_h*g}{(m_h+m_c)}

a = \frac{0.894*242*9.8}{(242+224)}

a = 4.54 m/s^2

Therefore the acceleration the horse can give is 4.54m/s^2

3 0
3 years ago
Protons are found togather in a
k0ka [10]

Answer:

they are found in a nucleus

Explanation:

3 0
3 years ago
A nuclear fission power plant has an actual efficiency of 32%. If 0.18 MW of power are produced by the nuclear fission, how much
7nadin3 [17]

Answer:

 P₀ = 5.76 x 10⁻² MW

Explanation:

given,

efficiency of the power plant = 32%

Power produced by the nuclear fission = 0.18 MW

the power plant output = ?

using formula of efficiency

\eta = \dfrac{P_0}{P}

where P is the power produced in the power plant

          P₀ is the power output of the power plant

\eta = \dfrac{P_0}{P}

0.32 = \dfrac{P_0}{0.18}

 P₀ = 0.18 x 0.32

 P₀ =  0.0576 MW

 P₀ = 5.76 x 10⁻² MW

Power plant output is equal to  P₀ = 5.76 x 10⁻² MW

8 0
3 years ago
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