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3 years ago

How many moles are there in 73 g of aluminum?

Chemistry

1 answer:

Genrish500 [490]3 years ago

8 0

Answer:

da real answer would b 26.981538. let me kno if dis is not an option.

Explanation:

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5. Which one of these species is an ion?

Maksim231197 [3]

The species that represents an ion is B³+ (option A).

An ion is an atom or group of atoms bearing an electrical charge, such as the sodium and chlorine atoms in a salt solution.

Simply put, an ion is said to be an electrically charged atom. This refers to the difference in the number of protons and electrons in the atom of an element.

According to this question, the species with an electrical charge is B³+, hence, it represents an ion.

Learn more about ion at: brainly.com/question/14982375

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4 0

1 year ago

What is the normal pressure of a man

ziro4ka [17]

Answer:

normal blood pressure?

or is it something else

3 0

3 years ago

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Determine the empirical formulas for compounds with the following percent compositions:

White raven [17]

Answer: a) $CS_2$

b) $CH_2O$

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{15.8g}{12g/mole}=1.32moles$

Moles of S= $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{84.2g}{32g/mole}=2.63moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.32}{1.32}=1$

For S = $\frac{2.63}{1.32}=2$

The ratio of C : S = 1:2

Hence the empirical formula is $CS_2$

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For H = $\frac{6.7}{3.33}=2$

For O = $\frac{3.33}{3.33}=1$

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is $CH_2O$

5 0

3 years ago

identify the element in period 3 that requires the least amount of energy to remove the most loosely held electrons from a mole

OLga [1]

Answer:

The element is Na

Explanation:

Ionization energy is the energy needed to release the last electron from an atom in its ground state to the gaseous state. It is a periodic property that increases as we go through the periods of the periodic table, but decreases if we move in groups. Sodium has thr ionic radius (another periodic property) that is too large, making it easier to release the electron away, since it is too far from the nucleus.

3 0

3 years ago

So I ordered a moonstone crystal and I was wondering if it’s real and is there anything I need about it??

Artemon [7]

Mmmmmmmh prolly fake stone

8 0

3 years ago

Read 2 more answers