Answer:
Explanation:
From the given information:
Let y(t) be the amount of sugar in tank A at any time.
Then, the rate of change of sugar in the tank is given by:
The rate of the sugar coming into the tank is 0
Initial amount of sugar = 25 Pounds
Now; y(0) = 25
25 = Ce⁰
C = 25
So; y(t) = 25
Thus, the amount of sugar at any time t =
B) For tank B :
0.75 atm x 760 mm Hg/atm = 570 mm Hg
We use the following formula for calculating the density:
p = m/v
Where:
m = mass
v = volume
So, we have:
p = 46 /5
p = 9,2 g/cm³