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blagie [28]
3 years ago
11

A phosphorus atom and a chlorine atom are likely to form a covalent bond because both elements:

Chemistry
2 answers:
quester [9]3 years ago
5 0

Answer: Option (a) is the correct answer.

Explanation:

When there occurs sharing of electrons between the two combining atoms then the bond formed is known as a covalent bond. Whereas when there occurs transfer of electrons between the combining atoms then the bond formed is known as ionic bond.

An ionic bond is formed between a metal and a non-metal.

Both phosphorous and chlorine belongs to third period and both of them are non-metals.

Atomic number of P is 15 and its electronic distribution is 2, 8, 5. Atomic number of Cl is 17 and its electronic distribution is 2, 8, 7.

Therefore, in order to attain stability both P and Cl will combine with each other by sharing electrons and hence, they will form a covalent bond.

Thus, we can conclude that a phosphorus atom and a chlorine atom are likely to form a covalent bond because both elements are non-metals.

Jobisdone [24]3 years ago
4 0
A phosphorus atom and a chlorine atom are likely to form a covalent bond because both elements are nonmetals. 
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Answer:

K = Ka/Kb

Explanation:

P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?

P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka

PCl₃(g) + Cl₂(g) <---------> PCl₅(g) Kb

K = [PCl₃]/ ([P] [Cl₂]⁽³'²⁾)

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Kb = [PCl₅]/ ([PCl₃] [Cl₂])

Since [PCl₅] = [PCl₅]

From the Ka equation,

[PCl₅] = Ka ([P] [Cl₂]⁽⁵'²⁾)

From the Kb equation

[PCl₅] = Kb ([PCl₃] [Cl₂])

Equating them

Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])

(Ka/Kb) = ([PCl₃] [Cl₂]) / ([P] [Cl₂]⁽⁵'²⁾)

(Ka/Kb) = [PCl₃] / ([P] [Cl₂]⁽³'²⁾)

Comparing this with the equation for the overall equilibrium constant

K = Ka/Kb

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