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Triss [41]
2 years ago
15

Find the solution to the following: *

Mathematics
1 answer:
Trava [24]2 years ago
5 0

Answer:

First one: x = all real numbers

Second one: x = 0

Step-by-step explanation:

for the first one

given 8x+10=2(4x+5) we need to isolate the variable (x) using inverse operations

step 1 distribute the 2 to what is in the parenthesis ( 4x and 5 )

2 * 4x = 8x

5 * 2 = 10

now we have 8x + 10 = 8x + 10

step 2 subtract 8x from each side

8x - 8x = 0

8x - 8x = 0

now we have 10 = 10

subtract 10 from each side

10 - 10 = 0

10 - 10 = 0

we're left with 0 = 0 meaning that all real numbers are solutions

For the second one

given 3x-8=2(x-4) once again we need to isolate the variable using inverse operations

step 1 distribute the 2 to what is in the parenthesis (x - 4)

2 *x = 2x

2 * -4 = -8

now we have 3x - 8 = 2x - 8

step 2 add 8 to each side

-8 + 8 = 0

-8 + 8 = 0

now we have 2x = 3x

step 3 subtract 2x from each side

3x - 2x = x

2x - 2x = 0

we're left with x = 0

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Y=-7x+7

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6 0
3 years ago
Y = 2 cm x = 75 grams
Nookie1986 [14]

Answer:

Step-by-step explanation:

3 0
2 years ago
W=1000M-200 rearrange your make M the subject
Anton [14]

Answer:

M = \frac{w+200}{1000}

Step-by-step explanation:

Given

w = 1000M - 200 ( isolate 1000M by adding 200 to both sides )

w + 200 = 1000M ( divide both sides by 1000 )

\frac{w+200}{1000} = M

7 0
2 years ago
Step by step workout of ;<br> log x^3+log 5x=5 log 2-log 2/5
Charra [1.4K]

Answer:

x = 2

Step-by-step explanation:

log  \: {x}^{3}  + log \: 5x = 5log \: 2 - log \:  \frac{2}{5}  \\  \\  \therefore \: log( {x}^{3}  \times 5x) = log  {2}^{5} - log \:  \frac{2}{5}  \\  \\ \therefore \: log( 5{x}^{4}) = log 32 - log \:  \frac{2}{5} \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(32  \times  \frac{5}{2}  \bigg) \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(16  \times  5) \\  \\ \therefore \: 5{x}^{4}=  16  \times  5 \\  \\ \therefore \: {x}^{4}=   {2}^{4}   \\  \\  \huge \purple{ \boxed{\therefore \: {x} = 2}}

4 0
3 years ago
0 Example: Loan payments of $400 due 95 days ago and $700 due today
guapka [62]

Answer:

X=\$519.48

Step-by-step explanation:

From the question we are told that

Loan 1 X_1=\$400

Loan 1 due t_1=95days

Loan 2 X_2=\$700

Loan 2 duet_2=0days

Payment Y=\$600

Worth of money w=6\%

Payment due t=30days

Focal date t_f=125days

Generally \$400 was due 95days ago

Therefore

125+90=220days(total days to consider)

Therefore

300+400 =700 is due today

125days left

Given

600 due in 30days

125-30=95days

Generally the Final payment is mathematically given by

400(1+ 0.06*\frac{220}{365} ) + 700(1+0.06*\frac{125}{365} )=600(1+0.06*\frac{95}{365} )+X

X=1128.9692 - 609.3698

Therefore the

X=\$519.48

3 0
2 years ago
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