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Sphinxa [80]
3 years ago
7

Suppose that the microwave radiation has a wavelength of 12.4 cm . How many photons are required to heat 255 mL of coffee from 2

5.0 ∘C to 62.0 ∘C
Chemistry
1 answer:
vivado [14]3 years ago
5 0

Answer:

Explanation:

wavelength λ = 12.4 x 10⁻² m .

energy of one photon = h c / λ

= 6.6 x 10⁻³⁴ x 3 x 10⁸ /  12.4 x 10⁻²

= 1.6 x 10⁻²⁴ J .

Let density of coffee be equal to density of water .

mass of coffee = 255 x 1 = 255 g

heat required to heat up coffee = mass x specific heat x rise in temp

= 255 x 4.18 x ( 62-25 )

= 39438.3 J  .

No of photons required = heat energy required / energy of one photon

= 39438.3 / 1.6 x 10⁻²⁴

= 24649 x 10²⁴

= 24.65 x 10²⁷ .

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Answer:

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What is the activity coefficient of H in a solution containing 0.073 M HCl and 0.0090 M Ca(ClO4)2? A table of activity coefficie
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Answer:

The value is pH  =  1.22

Explanation:

From the question we are told that

The concentration of H^{+} is [H^{+}] =  0.073 \  M

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Generally the log of the activity coefficient is mathematically represented as

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\mu is the ionic strength which is mathematically represented as

\mu  =  \frac{1}{2}  *  \{  0.073* (+1)^2 +0.073 * (-1)^2+0.0090 * (+2)^2+ 0.018* (-1)^2   \}

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log  \  \gamma__{H^+}} =  \frac{-0.5(+1)^2 * \sqrt{0.1} }{1 + (900*10^{-12} *  \frac{\sqrt{0.1}}{305}  )}

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pH  =  -log [H^{+}] *  \gamma__{H^{+}}

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