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2 years ago

What is the bond formation of N and H

2 answers:

8 0

Hydrogen bonding between a water molecule and an ammonia (NH3) molecule. Note that the N atom in the NH3 molecule is attracted to H atom in the H20 molecule

Zielflug [23.3K]2 years ago

3 0

Answer:

A single bond, but it's also a hydrogen bond.

Explanation:

A hydrogen bond forms when hydrogen bonds to the 3 most electronegative atoms: Oxygen, Nitrogen, or Fluorine.

It's a single bond because hydrogen only has two valence electrons. Therefore, the rest of the electrons are placed around the nitrogen atom.

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• What type of rock is used for radiometric dating, Why?

sukhopar [10]

An igneous rock because its radiometric clock is reset, and potassiumargon measurements can be used to tell the number of years that have passed since metamorphism.

3 0

3 years ago

The reaction below is at equilibrium. What would happen if more carbon were

schepotkina [342]

Explanation:

$C_{(s)} + O_{2(g)} \rightleftharpoons CO_{2(g)}$

According to le ch-atelier's principle when a chemical reaction at equilibrium subjected to any stress, then the equilibrium shifts in that direction in which effect of stress is reduced.

When we would add more number of carbon in above reaction then rate of forward reaction will increase to attain the equilibrium again.

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5 0

2 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

3 years ago

What substance is oxidized in the following reaction? 4HCl + MnO2 → Cl2 + 2H2O + MnCl2

Blizzard [7]

Answer:

Cl⁻ was oxidized.

Explanation:

4HCl + MnO₂ → Cl₂ + 2H₂O + MnCl₂

Oxidation can be defined as the process in which the oxidation number of a substance increases.

On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.

Thus, Cl⁻ was oxidized.

8 0

3 years ago

How many MOLECULES are in 50.0 grams of lithium phosphate?

Ray Of Light [21]

Answer: 2.60 x 10^23 molecules

50.0 grams x (1 mol/115.79 grams) = 0.431816219 moles

0.431816219 mol x (6.02 x 10^23 molecules/1 mol) = 2.599533638 x 10^23 molecules (final answer is rounded)

8 0

3 years ago