Answer:
Three double bonds and no lone pairs of electrons- trigonal planar
Two single bonds and two lone pairs of electrons-bent
Five single bonds and no lone pairs of electrons- trigonal bipyramidal
Three single bonds and one lone pair of electrons- trigonal pyramidal
Two double bonds and no lone pairs of electrons - linear
Four single bonds and no lone pairs of electrons- tetrahedral
Six single bonds and no lone pairs of electrons- octahedral
Explanation:
The valence shell electron pair repulsion theory gives a description of the shape of a molecule based on the number of regions of electron density present on the valence shell of the central atom of the molecule.
The molecules are distorted away from the shape predicted on the basis of the VSEPR by the presence of lone pairs on the valence shell of the central atom in the molecule. In the absence of lone pairs, the shape of a molecule is exactly the shape predicted on the basis of the VSEPR theory.
Answer:
The metal probably increases reaction rate by either holding reactant molecules in the correct orientation to react or by weakening or breaking bonds in reactant molecules to make them more reactive.
This is an example of heterogeneous catalysis.
It is heterogeneous catalysis because the catalyst is a solid and the reactants are gases. In heterogeneous catalysis, the catalyst is in a different phase than the reactants
Explanation:
got it right :)
The theoretical yield of H₂S is 13.5 g.
The percent yield is 75.5 %.
<h3>What is the theoretical yield of H₂S from the reaction?</h3>
The equation of the reaction is given below:
Moles of FeS reacting = mass/molar mass
Molar mass of FeS = 88 g/mol
Moles of FeS reacting = 35/88 = 0.398 moles
Moles of H₂S produced = 0.398 moles
Molar mass of H₂S = 34 g/mol
Mass of H₂S produced = 0.398 * 34 = 13.5 g
Theoretical yield of H₂S is 13.5 g.
- Percent yield = actual yield/theoretical yield * 100%
Actual yield of H₂S = 10.2 g
Percent yield = 10.2/13.5 * 100%
Percent yield = 75.5 %
In conclusion, the actual yield is less than the theoretical yield.
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Explanation:
Specific heat capacity can be calculated using the following equation: q = mc∆T In the equation q represents the amount of heat energy gained or lost (in joules ), m is the mass of the substance (in grams), c is the specific heat capacity of the substance (in J/g °C), and ∆T is the temperature change of the substance