<u>Answer</u>:
In an ideal intercuspal position, the mesiofacial groove of a mandibular first molar opposes "A triangular ridge of the mesiofacial cusp" of the maxillary first molar
<u>Explanation</u>:
Triangular ridges are those which arises from the cusp guidelines of premolar and molars near the central groove. Transverse ridges are designed by the grouping of two triangular ridges on the posterior teeth. The connection of the buccal and lingual triangular ridges is frequently termed as an example. Being a non-functional cusp it is a mandibular tooth. The crown touches into lingually. The cusp has four cusp edges they are mesiobuccal, distobuccal, mesiolingual and distolingual. The buccal and lingual triangular edges will lead to the establishment of the transverse edge in the central groove part.
It's determined by the presence or absence of appropiate receptors.
Water is better solvent for salt as compared to oil because water is a polar solvent. The water molecules are tend to attract each other and other polar molecules also because of their polarity. The oil molecules are non polar hence, they will not attract to any other polar molecules. Therefore, water is a better solvent for salt as compared to oil.
Answer:
B
Explanation:
The evidence that prompt this conclusion is the reported amount of nucleotide present which is varied because double stranded DNA genome which is usually heavier, more stable usually contains Adenine to thymine ratio of 1 to 1 and guanine to cytosine ratio of 1 to 1 and an over all of 1 to 1 ratio of purines to pyrimidines ( Double-stranded genomes have equal amounts of A to C )compared to what is reported which has a varied ratio ( A to T is 1 : 3 and G to C is about 0.77 for ss stranded DNA).
Answer:
1.A single band of intermediate density.
Explanation:
According to semiconservative model of DNA replication, the two strands of one DNA molecule separate at the time of replication and each strand acts a template for a new strand. So, the resulting new DNA molecule has one old strand and one new strand.
Here, the E coli cells were grown originally in 14N medium. So all the DNA molecules had 14N strands. When they were transferred to a 15N medium, only 15N was available then for further replications. In the first round of replication in new medium, all the old 14N strands (14N14N) separated and formed a new strand each using 15N. Hence all the resulting DNA molecules had one 14N strand and one 15N strand (14N15N).
Since 14N is of lighter density and 15N is of heavier density, 14N15N strands will give band of intermediate density. Since after one round of replication all DNA molecules will be 14N15N, there will be only one band of intermediate density.
