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Jet001 [13]
2 years ago
7

If one mole of ozone gas has a mass of 47.997g, what is the mass of three moles of ozone gas?

Chemistry
1 answer:
Brums [2.3K]2 years ago
3 0

Answer:

143.991

Explanation:

47.997 * 3 = 143.991

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Opening a soda bottle illustrates how a decrease in pressure will___the amount of gas that can be dissolved in water.
strojnjashka [21]
C. Increase :)
I would choose C
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3 years ago
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Susan made observations about outside events she noticed throughout the day. The day began with rain. Susan saw puddles on the r
S_A_V [24]

Answer:

Rainfall - precipitation

disappeared puddles - evaporation

cloud formation - condensation

Explanation:

Rainfall that is observed by the Susan is the precipitation of the water cycle in which the water vapor that was condensed become heavy and form droplets of water and fall from sky to the earth surface.

Puddles that formed due to rainfall are the collection of water in the water cycle which is evaporated (process: evaporation) into the atmosphere n the form of water vapor which condensed to form clouds.

4 0
2 years ago
Explain the role of a primary consumer and a secondary consumer in a food web.
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Answer:

Explanation:

Secondary consumers are organisms that eat primary consumers for energy. Primary consumers are always herbivores, or organisms that only eat autotrophic plants.

Carnivores only eat other animals, and omnivores eat both plant and animal matter.

7 0
2 years ago
Which state of matter requires special conditions to form and is affected by electric and magnetic fields
amid [387]

Answer:

The uniqueness of the plasma state is due to the importance of electric and magnetic forces that act on a plasma in addition to such forces as gravity that affect all forms of matter.

Explanation:

3 0
2 years ago
A 1.00 L flask is filled with 1.15 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pres
tatiyna

Answer:

The partial pressure of argon in the flask = 71.326 K pa

Explanation:

Volume off the flask = 0.001 m^{3}

Mass of the gas = 1.15 gm = 0.00115 kg

Temperature = 25 ° c = 298 K

Gas constant for Argon R = 208.13 \frac{J}{kg k}

From ideal gas equation P V = m RT

⇒ P = \frac{m R T}{V}

Put all the values in above formula we get

⇒ P = \frac{0.00115}{0.001} × 208.13 × 298

⇒ P = 71.326 K pa

Therefore, the partial pressure of argon in the flask = 71.326 K pa

4 0
3 years ago
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