Transcribed image text: Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00g/mL .
<h3>
Answer:</h3>
3.3 × 10²³ molecules Cu(NO₃)₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
0.55 mol Cu(NO₃)₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
3.3121 × 10²³ molecules Cu(NO₃)₂ ≈ 3.3 × 10²³ molecules Cu(NO₃)₂
Answer:
Protons 4 or 5 are most acidic.
Explanation:
As mentioned there are four types of hydrogen in Hexane-2,4-dione.
The numbering are shown in the figure for your better understanding.
As shown in the figure if we remove the proton from carbon number 3 (protons number 4 or 5), it will result in formation of a carbanion. This carbanion is stabilized due to presence of -I group oxygen and there is possibility of resonance (as shown).
Thus protons 4 or 5 are most acidic.
Use the formula for volume. V = lwh. Plug in the numbers for length, width, and height. Now we have V = 4.0 x 2.0 x 1.0, which is 8.0. So the volume of the block is 8.0 cm.
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