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Lesechka [4]
3 years ago
7

What is the answer? Please

Chemistry
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

snail should be at the top

Explanation:

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Find the mass of a 60 ML volume of water if the density of water is 1 g/mL
valkas [14]

Answer:  60 grams

Explanation:  (60 ml)*(1g/ml) = 60g

3 0
3 years ago
The weight of a substance is defined as its mass divided by its volume. Please select the best answer from the choices provided
Alexus [3.1K]

Answer: The given statement is false.

Explanation:

Weight :It is defined as the measure of force exerted upon the object by the gravity. It is measured in Newtons.

W=mg, where W= Weight , m = mass of the object , g = acceleration due to gravity = 9.8m/s^2

Here the given statement is False, the correct statement will be:

The density of a substance is defined as its mass divided by its volume.

8 0
3 years ago
Read 2 more answers
a 0.1 kg slinky sits at the top of a staircase with 14 J of potential energy. How high is the staircase?
Bezzdna [24]

Answer: The staircase is 14.28 m high.

Explanation:

Given : Mass = 0.1 kg

Potential energy = 14 J

Potential energy is the energy occupied by the position of a substance. Therefore, formula for potential energy is as follows.

P.E = mgh

where,

m = mass

g = gravitational energy = 9.8 m/s^{2}

h = height of object

Substitute the values into above formula as follows.

P.E = m \times g \times h\\14 J = 0.1 kg \times 9.8 m/s^{2} \times h\\h = \frac{14 J}{0.1 kg \times 9.8 m/s^{2}}\\= \frac{14 J}{0.98 m kg/s^{2}}\\= 14.28 Js^{2}/ mkg          (1 J s^{2}/m kg = 1 m)\\= 14.28 m

Thus, we can conclude that the staircase is 14.28 m high.

5 0
3 years ago
Two gas-containers, A and B, are connected with a valve. The first container, A, has a volume of 135 mL, and the second containe
stiv31 [10]

Answer:

85.5 mmHg is the pressure of the gas sample when the valve is opened.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas in container A = 165 mmHg

P_2 = final pressure of gas = ?

V_1 = initial volume of gas in container A= 135 mL

V_2 = final volume of gas = 135 mL + 117 mL = 252 mL

T_1 = initial temperature of gas in container A = 22.5^oC=273+22.5=295.5 K

T_2 = final temperature of gas = 12.7^oC=273+12.7=285.7K

Now put all the given values in the above equation, we get:

P_2=\frac{P_1V_1\times T_2}{T_1\times V_2}

=\frac{165 mmHg\times 135 mL\times 285.7 K}{295.5 K\times 252 mL}

P_2=85.5 mmHg

85.5 mmHg is the pressure of the gas sample when the valve is opened.

8 0
4 years ago
Study this diagram of a flowering tree’s life cycle. What is the error in the diagram? A. stage 1 B. stage 2 C. stage 3 D. stage
Ksivusya [100]

c. . stage 3 hoped i helped with the question

6 0
3 years ago
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