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julia-pushkina [17]

2 years ago

9

Study this diagram of a flowering tree’s life cycle. What is the error in the diagram? A. stage 1 B. stage 2 C. stage 3 D. stage

4 E. stage 5

2 answers:

Ksivusya [100]2 years ago

6 0

c. . stage 3 hoped i helped with the question

jek_recluse [69]2 years ago

4 0

Answer:the answer is c: stage 3

Explanation:

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Heat Transfer Lab

scoray [572]

Heat Transfer Lab

The following represents a lab set up for heat transfer. The cup on the left started with boiling water at 100 degrees C and the cup on the right has water at 20 degrees C. There is an aluminum bar between the two cups allowing heat to transfer from one cup into the other. The set up will be left alone for 20 minutes and temperatures of each cup of water will be recorded every minute for 20 minutes.

mag-aral ka

5 0

2 years ago

What is difference between groups and periods? 8th grade science idk what to put it under

d1i1m1o1n [39]

One is rows the other is columns

7 0

2 years ago

33.56 g of fructose (C6H,206) and 18.88 g of water are mixed to obtain a 40.00 ml solution a. What is this solution's density? b

Darina [25.2K]

Explanation:

Mass of fructose = 33.56 g

Mass of water = 18.88 g

Total mass of the solution = Mass of fructose + Mass of water = M

M = 33.56 g + 18.88 g =52.44 g

Volume of the solution = V = 40.00 mL

Density = $\frac{Mass}{Volume}$

a) Density of the solution:

$\frac{M}{V}=\frac{52.44 g}{40.00 mL}=1.311 g/mL$

b) Molar mass of fructose = 180.16 g/mol

Moles of fructose = $n_1=\frac{ 33.56 g}{180.16 g/mol}=0.1863 mol$

Molar mass of water = 18.02 g/mol

Moles of water= $n_2=\frac{ 18.88 g}{18.02 g/mol}=1.0477 mol$

Mole fraction of fructose in this solution: $\chi_1$

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1863 mol}{0.1863 mol+1.0477 mol}$

$\chi_1=0.1510$

Mole fraction of water = $\chi_2=1-\chi_1=0.8490$

c) Average molar mass of of the solution:

= $\chi_1\times 180.16 g/mol+\chi_2\times 18.02 g/mol$

$=0.1510\times 180.16 g/mol+0.8490\times 18.02 g/mol=42.50 g/mol$

d) Mass of 1 mole of solution = 42.50 g/mol

Density of the solution = 1.311 g/mL

d) Specific molar volume of the solution:

$\frac{\text{Average molar mass}}{\text{Density of the mass}}$

$=\frac{42.50 g/mol}{1.311 g/mL}=32.42 mL/mol$

5 0

2 years ago

Moldear una plastilina es un cambio fisico o quimico.

Andrews [41]

Fisico

Explanation:

esto es debido a que el mismo no modifica la estructura química de la misma. ... Cambios químicos: son aquellos que producen un cambio en la estructura molecular de una sustancia, por lo general se producen mediante una reacción

6 0

3 years ago

A 350.0 ml sample of gas has a temperature of 22.7 C and a pressure of 0.914 atm. What temperature would be needed for the same

Rus_ich [418]

Answer:

Explanation:

We shall apply gas law formula

P₁ V₁ / T₁ = P₂V₂ / T₂

.914 x 350 / ( 273 + 22.7 ) = 1 x 220 / T₂

1.0818 = 220 / T₂

T₂ = 203.36 K

= - 69.64 ⁰ C

7 0

2 years ago