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julia-pushkina [17]
3 years ago
9

Study this diagram of a flowering tree’s life cycle. What is the error in the diagram? A. stage 1 B. stage 2 C. stage 3 D. stage

4 E. stage 5
Chemistry
2 answers:
Ksivusya [100]3 years ago
6 0

c. . stage 3 hoped i helped with the question

jek_recluse [69]3 years ago
4 0

Answer:the answer is c: stage 3

Explanation:

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1. Count them
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Matter is made up of tiny particles that are too small to be seen with the naked eye. these tiny particles are known as _______.
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15 pts The drop down items have the same options for all sections labeled choose an item
cricket20 [7]

8) 21.504 liters of gas

9) 122.5 g

10) 6.022*10^23

Explanation:

8)

1 mole= 22.4 liters

to calculate the volume of gas of 0.960 moles of CH4

22.4*0.960/1

= 21.504 liters of gas  

9)

2.0 mole*18.02 g/ 1 mole

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10)

2.0 l * 1 mole/22.4 l

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8 0
3 years ago
A 1.555-g sample of baking soda decomposes with heat to produce 0.991 g Na2CO3. Refer to Example Exercise 14.l and show the calc
Sunny_sXe [5.5K]

Answer:

a) 101%

b)59.7%

Explanation:

The equation for the thermal decomposition of baking soda is shown;

2NaHCO3 → Na2CO3 + H2O + CO2

Number of moles of baking soda= mass/molar mass= 1.555g/84.007 g/mol = 0.0185 moles

From the reaction equation;

2 moles of baking soda yields 1 mole of sodium carbonate

0.0185 moles of baking soda will yield = 0.0185 moles ×1 /2 = 9.25 ×10^-3 moles of sodium carbonate.

Therefore, mass of sodium carbonate= 9.25 ×10^-3 moles × 106gmol-1= 0.9805 g of sodium carbonate. This is the theoretical yield of sodium carbonate.

%yield = actual yield/theoretical yield ×100

% yield = 0.991/0.9805 ×100

%yield = 101%

Since ;

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And H2O + CO2 ---> H2CO3

Hence I can write, 2NaHCO3 → Na2CO3 + H2CO3

Molar mass of H2CO3= 62.03 gmol-1

Molar mass of baking soda= 84 gmol-1

Therefore, mass of baking soda=

0.325/62.03 × 2 × 84 = 0.88 g of NaHCO3

% of NaHCO3= 0.88/1.473 × 100 = 59.7%

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When did the first particles of matter originate
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