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IgorC [24]
3 years ago
14

The energy wasted in using a machine is 600j. if the machine is 70% efficient. calculate the volume of water pumb by the machine

through a height of 15m.​
Physics
1 answer:
WINSTONCH [101]3 years ago
3 0

Answer:

yhgigy6ftu5cg l8vbbnnbbgtccccvhklhaywje nc 62bbnzmakbdbvfvdbf93bdldmffmfkqhdv

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Genetics may cause you to become depressed easier, but your environment affects your mood and can affect your long term attitude.  Please mark Brainliest!!!
6 0
3 years ago
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When a condenser discharges electricity, the instantaneous rate of change of the voltage is proportional to the voltage in the c
e-lub [12.9K]

Answer:

460.52 s

Explanation:

Since the instantaneous rate of change of the voltage is proportional to the voltage in the condenser, we have that

dV/dt ∝ V

dV/dt = kV

separating the variables, we have

dV/V = kdt

integrating both sides, we have

∫dV/V = ∫kdt

㏑(V/V₀) = kt

V/V₀ = e^{kt}

Since the instantaneous rate of change of the voltage is -0.01 of the voltage dV/dt = -0.01V

Since dV/dt = kV

-0.01V = kV

k = -0.01

So, V/V₀ = e^{-0.01t}

V = V₀e^{-0.01t}

Given that the voltage decreases by 90 %, we have that the remaining voltage (100 % - 90%)V₀ = 10%V₀ = 0.1V₀

So, V = 0.1V₀

Thus

V = V₀e^{-0.01t}

0.1V₀ = V₀e^{-0.01t}

0.1V₀/V₀ = e^{-0.01t}

0.1 = e^{-0.01t}

to find the time, t it takes the voltage to decrease by 90%, we taking natural logarithm of both sides, we have

㏑(0.01) = -0.01t

So, t = ㏑(0.01)/-0.01

t = -4.6052/-0.01

t = 460.52 s

3 0
3 years ago
Um elétron é lançado entre duas placas eletrizadas como mostra a figura. Sejam v= 6x10^6 m/s, ângulo 45°, E= 2x10^3 N/C, d= 3 cm
Svetlanka [38]
B hdbdudegjegedbfdrjf
3 0
3 years ago
What can a drop of liquid mercury be described as
jeka94
It can be described as <span>a pure substance and an element. </span>
7 0
3 years ago
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A cat jumps off a piano that is 1.3m high. The initial velocity of the cat is 3m/s at an angle of 37degrees above the horizontal
SpyIntel [72]

Answer:

x=1.75m

Explanation:

From the exercise we have that

y_{o}=1.3m\\v_{o}=3m/s, \beta  =37\\

<em><u>To find how far from the edge of the piano does the cat strike the floor, we need to calculate its time first </u></em>

y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}

At the end of the motion y=0m

0=1.3+3sin(37)t-\frac{1}{2}(9.8)t^{2}

Solving for t

t=-0.36 s or t=0.73s

Since the <u>time</u> can't be negative the answer is t=0.73

Knowing that we can calculate how far does the cat strike the floor

x=v_{ox}t=3cos(37)(0.73)=1.75m

6 0
3 years ago
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