Answer:
Car travel a distance of 60.06 m in 6 sec
Explanation:
We have given initial velocity v = 20 m/sec
Time = 6 sec
As the car stops finally so final velocity v = 0
From the first equation of motion
v = u+at (as the car velocity is slows down means it is a case of deceleration)
So v = u-at
![0=20-a\times 6](https://tex.z-dn.net/?f=0%3D20-a%5Ctimes%206)
![a=3.33m/sec^2](https://tex.z-dn.net/?f=a%3D3.33m%2Fsec%5E2)
Now from second equation of motion
Answer:
3.185×10^-29 kgm/s
Explanation:
Momentum(p)=mass×velocity
=9.1×10^-31×3.5×10
=3.185×10^-29 kgm/s
Answer:
Given mass = 2kg, height = 10m,g = 9.8.
We know that Work done W = FD
= > W = (mg)(D)
= > W = (2 * 9.8)(10)
= > W = 196 Joules.
Explanation:
Yan :).
A catalyst lessens the energy for a reaction so it can speed up so the catalyst is not used up in the end of the reaction so the answer would be D.