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In-s [12.5K]
3 years ago
15

Need help with this ASAP ILL LOVE U FOREVER

Mathematics
2 answers:
Paha777 [63]3 years ago
7 0

Answer:its easy it the first one you had posted

Step-by-step explanation:

IRISSAK [1]3 years ago
3 0

Answer:

substitute x for -36 and y for 58

Step-by-step explanation:

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[khan academy] <br><br> hello, please help me with this if youre able to, thanks uwu
Ostrovityanka [42]

Answer:

11 units

Step-by-step explanation:

To calculate CD use the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = C(- 4, 6) and (x₂, y₂ ) = D(- 4, - 5)

CD = \sqrt{(-4+4)^2+(-5-6)^2}

     = \sqrt{0^2+(-11)^2}

     = \sqrt{0+121} = \sqrt{121} = 11

6 0
3 years ago
Read 2 more answers
How to put a starting pay of $500 with 100% increase every month on a graph.
ohaa [14]

Answer:

if boo ygdv

Step-by-step explanation:

f bi igfcnkyf f jurf

4 0
2 years ago
How do you draw a two dimensional shape that has four angles in all show a picture
Talja [164]
You should search it on youtube becouse pepople cant really explain or draw the shape to show you
6 0
3 years ago
3.8*10 to the 9th power divided by 4*10 to the 2nd power
user100 [1]

Answer:

9.5\times 10^{6}

Step-by-step explanation:

1. Divide the coefficients and the exponentials separately

\dfrac{3.8 \times 10^{9}}{4 \times 10^{2}} = \dfrac{3.8}{4} \times \dfrac{10^{9}}{10^{2}}

2. Divide the coefficients

\dfrac{3.8}{4} = 0.95

3. Divide the exponentials

Subtract the exponent in the denominator from the exponent in the numerator.

\dfrac{10^{9}}{10^{2}} = 10^{(9 - 2)} = 10 ^{7}

4. Re-join the new coefficient and the new exponential

\dfrac{3.8 \times 10^{9}}{4 \times 10^{2}} = 0.95 \times 10^{7}

5. Put the new number into standard form

The number before the power of 10 must be greater than or equal to one and less than 10.

Multiply the answer by 10/10.

(0.95 \times 10^{7}) \times \dfrac{10}{10} = (0.95\times10) \times \dfrac{10^{7}}{10} = \mathbf{9.5\times 10^{6}}

5 0
3 years ago
The accompanying data represent the miles per gallon of a random sample of cars with a​ three-cylinder, 1.0 liter engine.a. Comp
Kobotan [32]

Answer:

1). Z score = 1.464733

Mean = 38.87917

Standard deviation = 3.609405

2). Quartiles:

Q1 = 37.025

Q2 = 38.450

Q3 = 40.800

3). IQR = 3.775

4).

CI (lower fence) = 37.4351

CI (upper fence) =  40.32323

5). There is outlier in the data set. Please see attached box plot for evidence.

Step-by-step explanation:

1). By Z score, we mean:

Z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}},

where:

x-bar ==> mean(g) = 38.87917

\mu = 37.80

standard deviation = 3.609405

sample size (n) = 24.

2). By quantile, we mean:

Q = L + (i*(n/4) - Cf)*c

Where L is the lower class limit of the quartile class

Cf is the cumulative frequency before the quartile class

c  is the class size.

3) . IQR = Q3 - Q1

4). CI = \mu \pm *Z_{\alpha/2} \frac{\sigma}{\sqrt{n}},

Where Z_{\alpha/2}  ==> 1.96

In order to replicate and obtain the result, please use the R code below:

g = c(31.5, 36.0, 37.8, 38.5, 40.1, 42.2,34.2, 36.2, 38.1, 38.7, 40.6, 42.5,34.7, 37.3, 38.2, 39.5,  

41.4, 43.4,35.6, 37.6, 38.4, 39.6, 41.7, 49.3)

boxplot(g)

Z = (mean(g) - 37.8)/(sd(g)/sqrt(length(g)))

mean(g)

quantile(g)

IQR(g)

CIl = mean(g) - 1.96*(sd(g)/sqrt(length(g)))

CIU = mean(g) + 1.96*(sd(g)/sqrt(length(g)))

4 0
3 years ago
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