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madreJ [45]
3 years ago
8

How fast is a ball going when it hits the ground after being dropped from a

Physics
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

Option D.

Explanation:

Data:

  • Height (h) = 9 m
  • Gravity (g) = 9.8 m/s²
  • Velocity Final (Vf) = ?

Use formula:

  • Vf² = 2 * g * h

Replace:

  • Vf² = 2 * 9.8 m/s² * 9 m

Multiply gravity with height:

  • Vf² = 2 * 88.2

Multiply:

  • Vf² = 176.4

Solve the square root:

  • Vf = 13.3

How fast is the ball going?

The speed is going at a speed of <u>13.3 meters per second.</u>

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As part of a NASA experiment, golfer Tiger Woods drives a golf ball on the moon, where g = 1.60 m/s2. He launches a golf ball wi
Elanso [62]

Answer:

Horizontal distance, R = vo2 sin(2x45)/g

v = 285 km/h = 79.17 m/s

R = 79.172 x 1/1.6

R = 3917 m

R = 3.9 km

8 0
3 years ago
In a particular run of the “Archimedes principle” experiment a particular unknown substance is found to have a “dry mass” of 4.5
iris [78.8K]

Answer:

D = 18000 kg/m3

V = 2.5*10{-7}m3

Explanation:

From the Archimedes principle,

Weight of fluid displaced = W_{air} - W_{water}

W_{air} = 4.5 gm

W_{water} = 4.25 gm

W = [4.5 - 4.25]*9.81*10^{-3}

W = 2.4525*10{-3} N

\frac{density\ of\ object}{density\ of\ fluid} = \frac{weight\ in\ air}{weight\ of\ displaced\ fluid}

Density\ of\ object = \frac{D_{water}*Weight\ in\ air}{weight\ of\ displaced\ water}

D = \frac{1000*4.5*10^{-3}*9.8}{2.4525*10^{-3}}N

D = 18000 kg/m3

b) object Volume can be obtained  as ,

V = \frac{m}{D} = \frac{4.5*10^{-3}}{18000}

V = 2.5*10{-7}m3

7 0
3 years ago
A 0.12-kg metal rod carrying a current of current 4.1 A glides on two horizontal rails separation 6.3 m apart. If the coefficien
Neporo4naja [7]

Answer:

The magnetic field is B  =  8.20 *10^{-3} \  T

Explanation:

From the question we are told that

   The  mass of the metal rod is  m  = 0.12 \ kg

    The current on the rod is  I  = 4.1 \ A

    The distance of separation(equivalent to length of the rod ) is L   = 6.3 \ m

     The coefficient of kinetic friction is \mu_k  =  0.18

      The kinetic frictional force is  F_k  = 0.212 \ N

     The constant speed is v  = 5.1 \ m/s

Generally the magnetic force on the rod is mathematically represented as  

      F  =  B * I  *   L

For  the rod to move with a constant velocity the magnetic force must be equal to the kinetic frictional force so

        F_ k  =  B*  I  *  L

=>      B  =  \frac{F_k}{L  *  I  }

=>       B  =  \frac{0.212}{ 6.3   *  4.1   }

=>       B  =  8.20 *10^{-3} \  T

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3 years ago
What is the ideal mechanical advantage of a ramp with a height of 3.5 and a length of 14.0 meters
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Answer:

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Explanation:

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