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2 years ago

How fast is a ball going when it hits the ground after being dropped from a

Physics

1 answer:

Umnica [9.8K]2 years ago

3 0

Answer:

Option D.

Explanation:

Data:

Height (h) = 9 m
Gravity (g) = 9.8 m/s²
Velocity Final (Vf) = ?

Use formula:

Vf² = 2 * g * h

Replace:

Vf² = 2 * 9.8 m/s² * 9 m

Multiply gravity with height:

Vf² = 2 * 88.2

Multiply:

Vf² = 176.4

Solve the square root:

Vf = 13.3

How fast is the ball going?

The speed is going at a speed of <u>13.3 meters per second.</u>

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A runner completes the 200-meter dash with a time of 19.80 seconds. What was the runner's average speed in miles per hour?

andriy [413]

Answer:

v = 22.54 mph.

Explanation:

Given that,

Distance moved, d = 200 m

Time, t = 19.8 s

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2 years ago

In the figure, a weightlifter's barbell consists of two identical small but dense spherical weights, each of mass 50 kg. These w

kondaur [170]

The moment of inertia is $24.8 kg m^2$

Explanation:

The total moment of inertia of the system is the sum of the moment of inertia of the rod + the moment of inertia of the two balls.

The moment of inertia of the rod about its centre is given by

$I_r = \frac{1}{12}ML^2$

where

M = 24 kg is the mass of the rod

L = 0.96 m is the length of the rod

Substituting,

$I_r = \frac{1}{12}(24)(0.96)^2=1.84 kg m^2$

The moment of inertia of one ball is given by

$I_b = mr^2$

where

m = 50 kg is the mass of the ball

$r=\frac{L}{2}=\frac{0.96}{2}=0.48 m$ is the distance of each ball from the axis of rotation

So we have

$I_b = (50)(0.48)^2=11.5 kg m^2$

Therefore, the total moment of inertia of the system is

$I=I_r + 2I_b = 1.84+ 2(11.5)=24.8 kg m^2$

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3 years ago

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