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jeyben [28]
3 years ago
5

How do i set this up

Physics
1 answer:
Ksivusya [100]3 years ago
7 0
What course is this
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Explain two ways friction can be reduced
BlackZzzverrR [31]
Friction can be reduced by making a surface smooth. It can also be reduced by applying lubricants such as oil and grease
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3 years ago
Two students stand poised to leap off a high dive structure into the swimming pool below. Student B is twice as massive as stude
iogann1982 [59]

Answer: option (D)

Explanation:

The potential energy of each of the students is given below as

P.E(student A) = mgh, where m = mass of student A, g is acceleration due to gravity and h = height of the high dive structure.

The mass of student B is twice as much as that of A, hence his mass is 2m and his potential energy is given below as

P.E ( student B) =2mgh = 2(mgh)

Recall that the relationship between potential energy and work done is that

Work done = - (change in potential)

For student A, work done = - mgh

For student B, work done = - 2mgh

From the equations above it can be seen that student B will do twice the work in getting to the high dive structure than student A hence validating option D.

8 0
3 years ago
If current in a wire of a blender is 8.2 A, how long would it take for 48 C of charge to pass a point in this wire ?
meriva

Explanation:

Approximately 5.9. Using Q=IT then T=Q/I so T=48/8.2=5.8536585366 Hope this helps

7 0
3 years ago
If an automobile airbag inflates in 25 µs, what is the time in seconds?
kotegsom [21]
That is 19 seconds cuz of the fast inplosion
7 0
3 years ago
(I) A novice skier, starting from rest, slides down an icy frictionless 8.0° incline whose vertical height is 105 m. How fast is
Vlad1618 [11]

Answer:

v = 45.37 m/s

Explanation:

Given,

angle of inclination = 8.0°

Vertical height, H  = 105 m

Initial K.E. = 0 J

Initial P.E. = m g H

Final PE = 0 J

Final KE = \dfrac{1}{2}mv^2

Using Conservation of energy

KE_i + PE_i + KE_f + PE_f

0 + m g H = \dfrac{1}{2}mv^2 + 0

v = \sqrt{2gH}

v = \sqrt{2\times 9.8 \times 105}

v = 45.37 m/s

Hence, speed of the skier at the bottom is equal to v = 45.37 m/s

3 0
3 years ago
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