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Ainat [17]
2 years ago
9

Does mass affect the final velocity of an object if the object begins with a high initial velocity? Why or why not?

Physics
1 answer:
luda_lava [24]2 years ago
5 0
The speed of a falling object<span> is </span>not affected<span> by the </span>mass<span> of the </span>object<span> ... This means that </span>if<span> both accelerate at the same rate, then the force acting on </span>objects<span> of different ... time and </span>initial velocity<span> and</span>not<span> dependent on the </span>mass<span> of the </span>object<span> at all</span>
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Explanation:

1The study of science and engineering should produce a sense of the process of argument necessary for advancing and defending a new idea or an explanation of a phenomenon and the norms for conducting such arguments. In that spirit, students should argue for the explanations they construct, defend their interpretations of the associated data, and advocate for the designs they propose. (NRC Framework, 2012, p. 73)

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8 0
2 years ago
two barges full of salted toad guts have a collision. the red barge has a mass of 150000kg and is traveling northwest at 0.25m/s
solniwko [45]

The final velocity of the red barge in the collision elastic is 0.311 m/s when it collides with blue barge pf mass 1000000 kg.

Final velocity(v3)  of the red barge is calculated by following formula

m1×v1+ m2×v2= (m1+m2)v3

Substituting the value of m1= 150000 kg, v1= 0.25 m/s, m2= 1000000 kg, v2= 0.32 m/s

150000 × 0.25+ 1000000×0.32= (150000+1000000)×v3

37500+ 320000= 1150000×v3

357500= 1150000×v3

v3= 0.311 m/s

<h3>What is elastic collision velocity? </h3>
  • The velocity of the target particle after a head-on elastic impact in which the projectile is significantly more massive than the target will be roughly double that of the projectile, but the projectile velocity will remain virtually unaltered.

For more information on elastic collision velocity kindly visit to

brainly.com/question/29051562

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6 0
1 year ago
A horizontal force of 400 N is exerted on a 2.0-kg ball as it rotates (at
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Answer:

the speed of the ball is 10 m/s

Explanation:

Given;

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mass of the ball, m = 2 kg

radius of the circle, r = 0.5

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F = \frac{mv^2}{r} \\\\v^2 = \frac{Fr}{m}\\\\v = \sqrt{\frac{Fr}{m}}\\\\ v = \sqrt{\frac{400*0.5}{2}}\\\\v = 10 \ m/s

Therefore, the speed of the ball is 10 m/s

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Answer:

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