1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ainat [17]
2 years ago
9

Does mass affect the final velocity of an object if the object begins with a high initial velocity? Why or why not?

Physics
1 answer:
luda_lava [24]2 years ago
5 0
The speed of a falling object<span> is </span>not affected<span> by the </span>mass<span> of the </span>object<span> ... This means that </span>if<span> both accelerate at the same rate, then the force acting on </span>objects<span> of different ... time and </span>initial velocity<span> and</span>not<span> dependent on the </span>mass<span> of the </span>object<span> at all</span>
You might be interested in
А<br> is a push or pull.
guajiro [1.7K]

Answer:

A

Explanation:

ignore this on...............................

7 0
3 years ago
Tom is throwing an baseball at an aluminum can,
pishuonlain [190]

Answer:

The question relates to the conservation of energy principle, the conservation of the linear momentum, and Newton's Laws of motion

Part A

1) Tom throwing a baseball at a can

The initial velocity of the baseball = v₂

The initial kinetic energy of the baseball, K.E.₂ = (1/2)·m₂·v₂²

∴ The final kinetic energy of the baseball, K.E.₂' = (1/2)·m₂·v₂'² < (1/2)·m₂·v₂²

Therefore, the energy of the ball before the collision is lesser than the energy of the ball after the collision

2) The evidence that would likely support the claim is that the baseball's height above the ground reduces rapidly immediately after the collision which is due to the reduced velocity, and therefore, the reduced (kinetic) energy

The final velocity of the baseball v₂' < v₂

Part B

1) The argument

The initial velocity of the can = v₁ = 0 (The can is initially  at rest)

The initial kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² = 0

The final velocity of the can v₁' > v₁ = 0

∴ The final kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² > 0

Given that the velocity of the can increases from zero to a positive value after collision with the baseball, the kinetic energy of the can is increased from zero before the collision to a positive value after the collision

2) An evidence in support of the argument is the motion of the can which was initially at rest which is an indication of increase in energy podded by the can

Explanation:

8 0
2 years ago
If two particles have equal kinetic energies, are their momenta necessarily equal? explain.
Mandarinka [93]

Answer:

No the given statement is not necessarily true.

Explanation:

We know that the kinetic energy of a particle of mass 'm' moving with velocity 'v' is given by

K.E=\frac{1}{2}mv^{2}

Similarly the momentum is given by m\times v

For 2 particles with masses m_{1},m_{2}and moving with velocities v_{1},v_{2} respectively the respective kinetic energies is given by

K.E_{1}=\frac{1}{2}m_{1}v_{1}^{2}

K.E_{2}=\frac{1}{2}m_{2}v_{2}^{2}

Similarly For 2 particles with masses m_{1},m_{2}and moving with velocities v_{1},v_{2} respectively the respective momenta are given by

p_{1}=m_{1}\times v_{1}

p_{2}=m_{2}\times v_{2}

Now since it is given that the two kinetic energies are equal thus we have

\frac{1}{2}m_{1}v_{1}^{2}=\frac{1}{2}m_{2}v_{2}^{2}\\\\(m_{1}v_{1})\times v_{1}=(m_{2}v_{2})\times v_{2}\\\\p_{1}\times v_{1}=p_{2}\times v_{2}\\\\\therefore \frac{p_{1}}{p_{2}}=\frac{v_{2}}{v_{1}}............(i)

Thus we infer that the moumenta are not equal since the ratio on right of 'i' is not 1 , and can be 1 only if the velocities of the 2 particles are equal which becomes a special case and not a general case.

5 0
3 years ago
A 3.5 kilogram object is swung in a circular path on the end of a 0.4 meter long string. the object makes one trip around the ci
jeyben [28]
Path length is 2*pi*0.4=2.512
Speed=distance/time
Speed =2.512/0.2=12.56m/s
6 0
3 years ago
A 0.05-kg car starts from rest at a height of 0.95 m. Assuming no friction, what is the kinetic energy of the car when it reache
statuscvo [17]
The kinetic energy of the car is A.) 0.466 J
6 0
2 years ago
Read 2 more answers
Other questions:
  • 20. Consider two Stars A and B with temperatures Ta and TB and radii Ra and RB respectively. If TA
    12·1 answer
  • Young’s modulus is property of gas
    7·1 answer
  • Consider the interference/diffraction pattern from a double-slit arrangement of slit separation d = 6.60 um and slit width a. Th
    5·1 answer
  • Mr smith is designing a race where velocity will be measured.which course would allow velocity to accurately get a winner?
    13·1 answer
  • How much work did the movers do (horizontally) pushing a 41.0-kg crate 10.6 m across a rough floor without acceleration, if the
    11·1 answer
  • What is most likely the author’s motive for writing this article?
    9·2 answers
  • The average lifespan of an incandescent lightbulb (at 60 W) is 1,200 hours. How much energy does the incandescent lightbulb use
    8·1 answer
  • Suppose a scoentist was able to construct a barometer with a liquid being denser than mercury , then how high would the liquid r
    15·1 answer
  • What happens to our bodies if we do not eat nutritious meals? give three reasons.​
    10·2 answers
  • Which type of energy is the energy of a moving tennis ball
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!