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Ainat [17]
3 years ago
9

Does mass affect the final velocity of an object if the object begins with a high initial velocity? Why or why not?

Physics
1 answer:
luda_lava [24]3 years ago
5 0
The speed of a falling object<span> is </span>not affected<span> by the </span>mass<span> of the </span>object<span> ... This means that </span>if<span> both accelerate at the same rate, then the force acting on </span>objects<span> of different ... time and </span>initial velocity<span> and</span>not<span> dependent on the </span>mass<span> of the </span>object<span> at all</span>
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Why is it important to use placebos and a double-blind approach in some studies
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3 years ago
Two children ride side-by-side on a carousel. Their paths are shown in the image below.
Sonbull [250]

Answer:

The child represented by a star on the outside path.

Explanation:

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3 years ago
Ann (mass 50 kg) is standing at the left end of a 15-m-long, 500 kg cart that has frictionless wheels and rolls on a frictionles
ivanzaharov [21]

Answer:

13.5 m

Explanation:

M = Mass of cart = 500 kg

m = Ann's mass = 50 kg

v_m = Velocity of Ann relative to cart = 5 m/s

v_M = Velocity of Cart relative to Ann

As the linear momentum of the system is conserved

Mv_M+mv_m=0\\\Rightarrow v_M=-\frac{mv_m}{M}\\\Rightarrow v_M=-\frac{50\times 5}{500}\\\Rightarrow v_M=-0.5\ m/s

Time taken to reach the right end by Ann

Time=\frac{Distance}{Speed}\\\Rightarrow Time=\frac{15}{5}=3\ s

Distance the cart will move in the 3 seconds

Distance=Speed\times Time\\\Rightarrow Distance=-0.5\times 3=-1.5\ m

The negative sign indicates opposite direction

Movement of Ann will be the sum of the distances

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The net movement of Ann is 13.5 m

5 0
3 years ago
What are the characteristics of high energy wave lengths
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3 years ago
A 79.7 kg base runner begins his slide into second base while moving at a speed of 4.77 m/s. The coefficient of friction between
SashulF [63]

To solve this problem we will apply the concept related to the kinetic energy theorem. Said theorem states that the work done by the net force (sum of all forces) applied to a particle is equal to the change experienced by the kinetic energy of that particle. This is:

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\Delta W = \frac{1}{2} mv^2

Here,

m = mass

v = Velocity

Our values are given as,

m = 79.7kg

v = 4.77m/s

Replacing,

\Delta W = \frac{1}{2} (79.7kg)(4.77m/s)^2

\Delta W = 907J

Therefore the mechanical energy lost due to friction acting on the runner is 907J

6 0
3 years ago
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