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miskamm [114]
3 years ago
5

An atom that has an outer shell that is NOT full is (more likely OR less likely) to be reactive than an atom that has a full out

er shell.
Chemistry
2 answers:
Rzqust [24]3 years ago
7 0

Answer:

An atom that has an outer shell that is NOT full is (more likely OR less likely) to be reactive than an atom that has a full outer shell.

Explanation:

Luba_88 [7]3 years ago
4 0

Answer:

more

Explanation:

logect

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which would have the longer wavelength, a photon with energy of 4.59 x 10^-19 J or a photon with energy of 3.01 x 10^-19 J
Eduardwww [97]
Compare them accordingly with the formula of E=hc/wavelength
6 0
4 years ago
What is the best description of the relationship between emerging scientific ideas and open-mindedness?
valentinak56 [21]

Answer:

The main relationship between emerging scientific ideas and open-mindedness is that for many new ideas to be accepted a population has to have an open mind, otherwise the new ideas are rejected without thought.

Explanation:

7 0
4 years ago
Blue eyes are recessive. Jonathan is hybrid for blue eyes. His wife Carly, has blue eyes. If they have four children, how many w
astraxan [27]

Answer:

possibly two

Explanation:

you said Jonathan had hybrid eyes, did you mean that he was heterozygous? if so 2 out of 4 will have the recessive gene "blue".

3 0
3 years ago
The volume of a given mass of an ideal gas at constant pressure is
zmey [24]

Answer:

inversely proportional to the kelvin temperature

Explanation:

PV=nRT

8 0
3 years ago
Read 2 more answers
A 50.0 g sample of scandium, sc, is heated by exposure to 1.50 x 10 3 j. The temperature of the sc is raised by 61.1 o
statuscvo [17]

Given mass of Scandium = 50.0 g

Increase in temperature of the metal when heated = 61.1^{0}C

Heat absorbed by Scandium = 1.50*10^{3}J

The equation showing the relationship between heat, mass, specific heat and temperature change:

Q = m C (deltaT)

Where Q is heat = 1.50*10^{3}J

m is mass = 50.0 g

ΔT = 61.1^{0}C

On plugging in the values and solving for C(specific heat) we get,

1.50*10^{3}J=50.0g(C)(61.1^{0}C)

C = 0.491\frac{J}{g^{0}C }

Specific heat of the metal = 0.491\frac{J}{g^{0}C }

7 0
4 years ago
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