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Rom4ik [11]
3 years ago
12

Which organelle allows plants to make their own food?

Chemistry
1 answer:
Setler [38]3 years ago
5 0

Answer:

chloroplast is the correct answer

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Simplify the numercial expression 13-2x5
Tema [17]

Answer:

3

Explanation:

2x5 is 10 then 13-10 is 3

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3 years ago
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Determine the empirical formula of an oxide of silicon from the following: mass of crucible= 18.20g, mass of crucible +silicon =
lyudmila [28]
The required empirical formula of the silicon oxide is SiO2.
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3 years ago
Which of the following is not a result when a change to an equilibrium system is applied? (2 points)
Ray Of Light [21]
It should be increasing the rate of the forward reaction will cause a shift to the left because the external stress, which is the increase in rate, will cause the reaction to be unbalanced, and to reach equilibrium it needs to shift to the right.
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3 years ago
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The air at the top of Mount Everest has pressures of 201.0 torr N2, 50.0 torr O2, 2.0 torr Ar, and 0.5 torr CO2. What is the tot
nordsb [41]

Answer:

The total air pressure at the top of the highest peak in the world is 253.5 torr

Explanation:

The partial pressures of the gases present at the top of Mount Everest are;

Nitrogen, N₂ = 201.0 torr

Oxygen, O₂ = 50.0 torr

Argon, Ar = 2.0 torr

Carbon dioxide, CO₂ = 0.5 torr

By Dalton's law of partial pressure, the total pressure that a mixture of gases exerts is equal to the sum of the partial pressures of the individual gases

Mathematically, the law can be expressed as follows;

Total pressure, P = ∑P_i = P₁ + P₂ + · · ·

From which we have;

The total air pressure at the top of the highest peak in the world, Mount Everest, P_{Total Mont Everest} = The sum of the partial pressures of N₂, O₂, Ar, and CO₂

P_{Total Mont Everest} = 201.0 torr + 50.0 torr + 2.0 torr + 0.5 torr = 253.5 torr

P_{Total Mont Everest} = 253.5 torr = 0.33355263 atmosphere

Therefore, the total air pressure at the top of the highest peak in the world,  P_{Total Mont Everest} = 253.5 torr

3 0
2 years ago
Lead has a density of 11.3 g/cm3. if you have 1.0 kg of lead, what is the volume in cubic centimeters (cm3)? remember to select
Novosadov [1.4K]
In this case, you are given the density( 11.3g/cm3) and the weight (1kg) of the lead. You are asked to find the volume of the lead.
To find volume you need to divide the weight with the density. It would be:
volume= weight/density
volume = 1kg x (1000 gram/kg) / (11.3g/cm3)= 88.495 cm3

4 0
3 years ago
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