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Rom4ik [11]
3 years ago
12

Which organelle allows plants to make their own food?

Chemistry
1 answer:
Setler [38]3 years ago
5 0

Answer:

chloroplast is the correct answer

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What happens to the air as it gets farther from the heat source?
Effectus [21]

Answer:

molecules heat and move faster, they are moving apart. So air, like most other substances, expands when heated and contracts when cooled.

Explanation:

Because there is more space between the molecules, the air is less dense than the surrounding matter and the hot air floats upward.

6 0
3 years ago
Do covalent bonds dissolve in methanol
ArbitrLikvidat [17]
Yes,covalent bonds do dissolve in methanol


5 0
3 years ago
A 40.0 milligram sample of 33p decays to 10.0 milligrams in 50.0 days. What is the half life of 33p?
il63 [147K]

Answer:

half life = 25 days

Explanation:

Given data:

Total amount of sample = 40 mg

Sample left after 50 days = 10 mg

Half life of P³³ = ?

Solution:

<em>1st step:</em>

when time is zero = 40 mg

1 half life = 40/2 = 20 mg

2 half life = 20/ 2= 10 mg

<em>2nd step:</em>

<em>Elapsed time/ half life = HL</em>

half life = 50 days/ 2

half life = 25 days

8 0
3 years ago
This is the type of attraction that holds elements like nickel, sodium and gold together. For these elements, stationary, positi
Andrew [12]

The answer is metallic bonding as this bond is the one responsible of having to provide attraction in the electrons and atoms that could lead of having substance to be made as a glue in order to provide definite structure and it explains the description above.

3 0
3 years ago
Read 2 more answers
In a 1.0x10^-4 M solution of HClO(aq), identify the relative molar amounts of these species:HClO, OH-, H3O+, OCl-, H2O
yarga [219]
HClO is a weak acid, which means the ions do not fully dissociate. The hydrolysis reaction for the hypochlorous acid is:

HClO + H2O ⇄ H3O+ +OCl-

Then the equilibrium constant, Ka, of dilute HClO would be:

K_{a} = \frac{[ H_{3}  O^{+} ][O Cl^{-} ]}{HClO}

Then we do the ICE table. I is for the initial concentration, C for the change and E for the excess.
      
          HClO       + H2O   ⇄   H3O+ +  OCl-
I     1.0x10^-4                          0             0
C        -x                                 +x           +x 
E  (1.0x10^-4 - x)                     x             x

Substituting the excess (E) concentration to the Ka equation:

K_{a} = \frac{[x ][x]}{1.0 \ x \  10^{-4} - x }

Simplifying the equation would yield a quadratic equation:

x^{2} + K_{a}x-(1.0 \ x \ 10^{-4}) K_{a}=0

The Ka for HClO is an experimental data which was determined to be 2.9 x 10^-8. Substitute this to the equation, determine the roots, then you get the value for x, which is the concentration of H3O+ and ClO-. Just use your calculator feature Shift-Solve.

x = 1.688 x 10^-6 M = [H3O+] = [ClO-]

Then, you can determine the conc of [OH-] through pH.

pH = -log {H3O+] = -log [1.688 x 10^-6] = 5.77
pOH = 14 - pH = 14 - 5.77 = 8.23
pOH = 8.23 = -log [OH-]
[OH-] = 5.89 x 10^-9 M

Also, since HClO is (1.0x10^-4 - x), then it's concentration would be:
[HClO] = 1.0x10^-4 - 1.688 x 10^-6 = 9.83 x10^-5 M

Let's summarize all concentrations:
[HClO] = 9.83 x10^-5 M
[OH-] = 5.89 x 10^-9 M
[H3O+] = [ClO-] = 1.688 x 10^-6 M
Since the solution is dilute, H2O is relatively higher in concentration.

Thus in relative amounts, the order would be

H2O >>> HClO > H3O+ = ClO- > OH-


6 0
3 years ago
Read 2 more answers
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