Remark
I think we are to assume that the line is a straight one and that it contains a total of 180o at the intersection.
Equation
2x + 7 + 6x - 9 = 180o
Solve
Combine the like terms on the left.
2x + 6x + 7 - 9 = 180
8x - 2 = 180o Add 2 to both sides.
8x - 2 + 2 = 180 + 2
8x = 182 Divide by 10
8x/8 = 182/8
x = 22.75
But that is not the answer.
You need to find 6x - 9
Angle = 6x - 9
Angle = 6*18.2 - 9
Angle = 127.5 <<<<< Answer.
Your answer is 7
5
+
3
4
−
3
−
2
+
6(7-4)+10
First distribute 6 into the parentheses
42-24+10= 28
So your answer is A. 28
Let the eq of circle be
x
2
+y
2
+2gx+2βy+c=0
now, x intercept = 2
g
2
−c
But circle touches x axis ∴ x intercept = 0
∴2
g
2
−c
=0∴g
2
=c
∴eq
n
become x
2
+y
2
+3gx+2βy+g
2
=0
Now circle passes through (3, 0) and (1, 4)
∴(3)
2
+(0)
2
+2g(3)+0+g
2
=0
9+6g+g
2
=0
∴g=−3
Also (1)
2
+(4)
2
+2(−3)(1)+2β(4)+9=0
∴1+16−6+8β+9=0
∴20+8β=0 ∴β=
2
5
Hence eq
n
of circle is
x
2
+y
2
−6x−5y+9=