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cestrela7 [59]
3 years ago
11

Explain and derive the equation for capillary action in the phenomenon of surface tension​

Physics
1 answer:
lapo4ka [179]3 years ago
3 0

Answer:

Explanation:Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, ... This article is about the physical phenomenon. ... If the diameter of the tube is sufficiently small, then the combination of surface tension (which is caused by cohesion ... They derived the Young–Laplace equation of capillary action.

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If an object is not moving are the forces acting on it balanced? Yes or no?why?
xxMikexx [17]

This is another time to look at Newton's 2nd law of motion:

Net Force = (mass) x (acceleration)

If the object is not moving, then its acceleration is certainly zero, and Newton's law looks like this:

Net Force = (mass) x (zero)

or  Net Force = (zero) .

"Net Force = zero" means that if there ARE any forces acting on the object, then they add up to zero, and we call them "balanced" forces.

So the answer is '<em>yes</em>', and that's why.

6 0
3 years ago
A student is creating a model of a concave lens. The diagram shows her incomplete model.
valentinak56 [21]

Answer:

D

Explanation:

I’m pretty sure it’s correct but I don’t really know. Just trying to pass science

8 0
3 years ago
Electrons contribute___
dangina [55]
C, electrons are negative, and most of the atom’s mass comes from the nucleus of the atom
4 0
3 years ago
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Irreversible damage to the liver due to long term alcohol abuse is called:
damaskus [11]

Answer:

A, Cirrhosis

Explanation:

3 0
3 years ago
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An electron experiences a magnetic force with a magnitude of 4.90×10−15 n when moving at an angle of 60.0 ∘ with respect to a ma
Leya [2.2K]
Missing questions: "find the speed of the electron".

Solution:
the magnetic force experienced by a charged particle in a magnetic field is given by
F=qvB \sin \theta
where
q is the particle charge
v its velocity
B the magnitude of the magnetic field
\theta the angle between the directions of v and B.

Re-arranging the formula, we find:
v= \frac{F}{qB \sin \theta}
and by substituting the data of the problem (the charge of the electron is q=1.6 \cdot 10^{-19} C), we find the velocity of the electron:
v= \frac{F}{qB \sin \theta}= \frac{4.90 \cdot 10^{-15}N}{(1.6 \cdot 10^{-19}C)(3.70 \cdot 10^{-3} T)(\sin 60^{\circ})}=9.56 \cdot 10^6 m/s
4 0
3 years ago
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