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qaws [65]
3 years ago
11

5. A person fishing from a pier observes that four wave crests pass by in 7.0 s and estimates that the distance between two succ

essive crests is 4.0 m. The timing starts with the first crest and ends with the fourth. What is the speed of the wave? BBoldIItalicsUUnderlineBulleted listNumbered listSuperscriptSubscript

Physics
1 answer:
TiliK225 [7]3 years ago
3 0

Answer:

v= 1.71 m/s

Explanation:

Given that

Distance between two successive crests = 4.0 m

 λ = 4 m

T= 7 sec

T is the time between 3 waves.

3 waves = 7 sec

1 wave = 7 /3 sec

So t= 7/3 s

We know that frequency f

f= 1/t= 3/7 Hz

Lets take speed of the wave is v

v= f λ

f=frequency

λ=wavelength

v= 3/7 x 4 = 12 /7

v= 1.71 m/s

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The correct answer is

D. Groups and Families

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3 years ago
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What will be the acceleration of a 40-kilogram object that is pushed with a net force of 80 newtons?
ratelena [41]
= 80 N/40 kg
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4 0
3 years ago
Two 125 kg bumper cars are moving toward each other in opposite directions. Car X is moving at 10 m/s and Car Z at −12 m/s when
nignag [31]
<h2>Given that,</h2>

Mass of two bumper cars, m₁ = m₂ = 125 kg

Initial speed of car X is, u₁ = 10 m/s

Initial speed of car Z is, u₂ = -12 m/s

Final speed of car Z, v₂ = 10 m/s

We need to find the final speed of car X after the collision. Let v₁ is its final speed. Using the conservation of momentum to find it as follows :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v₁ is the final speed of car X.

m_1u_1+m_2u_2-m_1v_1=m_2v_2\\\\m_2v_2=m_1u_1+m_2u_2-m_2v_2\\\\m_1v_1=125\times 10+125\times (-12)-125\times 10\\\\v_1=\dfrac{-1500}{125}\\\\v_1=-12\ m/s

So, car X will move with a velocity of -12 m/s.

3 0
3 years ago
Anyone know how this work ?? <br> If u know help me it is an exam
myrzilka [38]

Answer:

D) This is the correct answer

Explanation:

In this exercise the two ball loads are suspended by a thread.

To answer this exercise, let us remember that charges of the same sign repel and charges of a different sign attract.

Therefore, for the system to maintain equilibrium, the two charges must be of the same sign.

When examining the different proposals

A) in this case, as a sphere has no charge, there is no electric force and the induced charge is of the opposite sign, so the spheres attract each other

B) in this case there is an electric force, but being of a different sign, the force is attractive so the system is not in equilibrium

C) as the charges are of different magnitude the system does not have equal angles

D) This is the correct answer, since the charges have the same magnitude and are of the same sign, so the force is repulsive and is counteracted by the weight component

             F_e = W sin θ

6 0
3 years ago
An 16.00-kg object is suspended by a rope at some height, h if the object has a potential energy of 900.01j what is the objects
qwelly [4]

Answer:

5.740 m

Explanation:

PE = mgh

900.0 J = (16.00 kg) (9.8 m/s²) h

h = 5.740 m

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3 years ago
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