5. A person fishing from a pier observes that four wave crests pass by in 7.0 s and estimates that the distance between two succ
essive crests is 4.0 m. The timing starts with the first crest and ends with the fourth. What is the speed of the wave? BBoldIItalicsUUnderlineBulleted listNumbered listSuperscriptSubscript
1 answer:
Answer:
v= 1.71 m/s
Explanation:
Given that
Distance between two successive crests = 4.0 m
λ = 4 m
T= 7 sec
T is the time between 3 waves.
3 waves = 7 sec
1 wave = 7 /3 sec
So t= 7/3 s
We know that frequency f
f= 1/t= 3/7 Hz
Lets take speed of the wave is v
v= f λ
f=frequency
λ=wavelength
v= 3/7 x 4 = 12 /7
v= 1.71 m/s
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Answer:
Loss,
Explanation:
Given that,
Mass of particle 1,
Mass of particle 2,
Speed of particle 1,
Speed of particle 2,
To find,
The magnitude of the loss in kinetic energy after the collision.
Solve,
Two particles stick together in case of inelastic collision. Due to this, some of the kinetic energy gets lost.
Applying the conservation of momentum to find the speed of two particles after the collision.
V = 6.71 m/s
Initial kinetic energy before the collision,
Final kinetic energy after the collision,
Lost in kinetic energy,
Therefore, the magnitude of the loss in kinetic energy after the collision is 10.63 Joules.