Wavelength = Speed / Frequency = 340/200= 1.7m
Answer:
Dead lifting uses tho muscle fundamentals
Explanation:
Answer:
The answer is letter b. All of these should be considered when deciding on a report format.
Explanation:
A Professional Report is a type of formal document about a topic or information that is intended for a specific audience or purpose. The report's style of writing needs a lot of knowledge from the writer. Oftentimes, it involves the following important elements: <em>Title, Summary, Body, Discussion, Conclusion and Recommendation. </em>
The writer should write according to his target audience and purpose. He also needs to consider the length of his report, as well as the suitable words and sentences that he should use.
Thus, all of the choices are important in writing a professional report. So, the answer is letter b.
Answer:
* in a tube with both ends open
λ = 2L / n n = 1, 2, 3,…
* tube with one end open and the other closed.
λ = 4L / n n = (2n ’+ 1 )
Explanation:
When a sound wave enters a pipe, a resonance process occurs, whereby only some wavelengths can occur.
* in a tube with both ends open
in this case there are maximums at each end, so if the length of the had is L
λ = 2L 1st harmonic
λ = 2 L / 2 2nd harmonic
λ = 2L / 3
λ = 2L / n n = 1, 2, 3,…
* In the case of a tube with one end open and the other closed.
At the open end there is a belly and at the closed end a node
λ = 4L 1st harmonic
λ = 4L / 3 3rd harmonic
λ = 4L / 5
λ = 4L / n n = 1, 3, 5,… odd
n = (2n ’+ 1 ) where n’ are all integers
Answer:
0.57 m
Explanation:
First of all, we need to calculate the time it takes for the ball to cover the horizontal distance between the starting position and the crossbar. This can be done by analzying the horizontal motion only. In fact, the horizontal velocity is constant and it is
And the distance to cover is
d = 19 m
So the time taken is
Now we want to find how high the ball is at that time. The initial vertical velocity is
So the vertical position of the ball at time t is
where g = 9.8 m/s^2 is the acceleration of gravity. Substituting t = 2.04 s, we find
The crossbar height is 3.05 m, so the difference is
So the ball passes 0.57 m above the crossbar.
