1. A man throws a ball up with a velocity of 30 m/s. How high does it get?
1 answer:
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The change in momentum of the car is 6000 kg m/s
Explanation:
According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on the object, therefore:
where
is the change in momentum
I is the impulse exerted
For the car in this problem, the impulse received is
I = 6000 kg m/s (in the forward direction)
Therefore, the change in momentum of the car is equal to this value:
(in the forward direction)
We can also calculate what is the new momentum of the car. In fact, the initial momentum is
And so, the new momentum is
Learn more about impulse and momentum:
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Answer:
1) No, the car does not travel at constant speed.
2) V = 9 ft/s
3) No, the car does not travel at constant speed.
4) V = 5.9 ft/s
Explanation:
In order to know if the car is traveling at constant speed we need to derive the given formula. That way we get speed as a function of time:
V(t) = 2*t + 2 Since the speed depends on time, the speed is not constant at any time.
For the average speed we evaluate the formula for t=2 and t=5:
d(2) = 8 ft and d(5) = 35 ft
Again, for the average speed we evaluate the formula for t=1.8 and t=2.1:
d(1.8) = 6.84 ft and d(2.1) = 8.61 ft