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Kamila [148]
3 years ago
5

Rosa eats a peanut butter sandwich for lunch. Peanut butter contains a lot of protein, and bread is mostly starch. Rosa plans to

go for a run later this afternoon. Rosa is breathing normally. does she need from the food she ate and the air she breathes so that she can go on her run? (Sentence starter: The molecules Rosa needs from the food she eats and air she breathes are.
this science
Chemistry
1 answer:
kotykmax [81]3 years ago
8 0

Explanation:

Rosa eats a peanut butter sandwich for lunch. Peanut butter contains a lot of protein, and bread is mostly starch. Rosa plans to go for a run later this afternoon. Rosa is breathing normally. does she need from the food she ate and the air she breathes so that she can go on her run? (Sentence starter: The molecules Rosa needs from the food she eats and air she breathes are.

this science

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According to the kinetic molecular theory, which statement describes the particles of an ideal gas? -1)The motion of the gas par
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A volume of 500.0 mL of 0.160 M NaOH is added to 585 mL of 0.200 M weak acid ( K a = 1.28 × 10 − 5 ) . What is the pH of the res
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Answer : The pH of the resulting buffer is, 5.22

Explanation : Given,

K_a=1.28\times 10^{-5}

First we have to calculate the moles of NaOH\text{ and }HA

\text{Moles of }NaOH=\text{Concentration of }NaOH\times \text{Volume of solution}}=0.160M\times 0.500L=0.08mol

and,

\text{Moles of }HA=\text{Concentration of }HA\times \text{Volume of solution}}=0.200M\times 0.585L=0.117mol

The balanced chemical reaction is:

HA+(aq)+OH^-(aq)\rightarrow H_2O(l)+A^-(aq)

Moles of HA left = 0.117 mol - 0.08 mol = 0.037 mol

Moles of A^- = 0.08 mol

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (1.28\times 10^{-5})

pK_a=5-\log (1.28)

pK_a=4.89

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[A^-]}{[HA]}

Now put all the given values in this expression, we get:

pH=4.89+\log (\frac{0.08}{0.037})

pH=5.22

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The catalyst used in Habers process is iron.

The balanced chemical reaction is:

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