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ehidna [41]
3 years ago
15

What is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants?

Chemistry
1 answer:
andrezito [222]3 years ago
8 0

Answer : The correct net ionic equation is:

Ba^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2H_2O(l)+BaSO_4(s)

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

Ba(OH)_2(aq)+H_2SO_4(aq)\rightarrow 2H_2O(l)+BaSO_4(s)

The complete ionic equation in separated aqueous solution will be,

Ba^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2H_2O(l)+BaSO_4(s)

In this equation, spectator ions are not present.

The correct net ionic equation is:

Ba^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2H_2O(l)+BaSO_4(s)

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il63 [147K]
First write out the balanced equation. 3Cu+2Ag(NO3)3=2Ag+3Cu(NO3)2
Then convert copper from grams to moles
15 g*1 mol cu/63.54 g= 15/63.54 mol cu
Then use the mole ratio to convert Moles Cu to Moles Ag
15/63.54 moles Cu* 2 moles Ag/3 moles Cu
The final awnser is (15*2)/(63.54*3) moles Ag =0.157 moles Ag. If the question wants the answer in grams, convert from moles Ag to grams Ag.
0.157 moles Ag*107.87 g Ag/ mol Ag=16.98 g Ag
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The answer is Agree :)
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Answer:

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Explanation:

8 0
3 years ago
Is this equation completely balanced? 2C8H8 + 25O2 8CO2 + 18H2O No, because the number of carbon, hydrogen &amp; oxygen atoms on
Sergio039 [100]
<span>So to make it clear let's break the equation down species by species and assess the number of each species on bothe sides of the equation:
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LHS:  C - 16                                           RHS:  C - 8
          H - 16                                                     H - 36
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Thus based on that it is evident that the equation is not quite balanced.  This therefore means a "</span><span>No, because the number of carbon, hydrogen & oxygen atoms on both sides of the equation are not equal."

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3 years ago
Consider the first-order reaction shown here. the yellow spheres in the pictures to the right represent the reactant,
Luda [366]
The rate constant of the reaction K we can get it from this formula:

K=㏑2/ t1/2 and when we have this given (missing in question):
that we have one jar is labeled t = 0 S and has 16 yellow spheres inside and the jar beside it labeled t= 10 and has 8 yellow spheres and 8 blue spheres and the yellow spheres represent the reactants A and the blue represent the products B

So when after 10 s  and we were having 16 yellow spheres as reactants and becomes 8 yellow and 8 blue spheres as products so it decays to the half amount so we can consider T1/2 = 10 s
a) by substitution in K formula:
∴ K = ㏑2 / 10 = 0.069 
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b) so no.of yellow spheres after 20 s (2 half-lives) =  16/2^2 = 4
and the blue spheres = Ao - no.of yellow spheres left = 16 - 4 = 12
c) The no.of yellow spheres after 30 s (3 half-lives) = 16/2^3 = 2
and the blue spheres = 16 - 2 = 14

8 0
3 years ago
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