Answer:
105m/3hourz
Explanation:
35 miles per hour, so 3 hours
35x3=105 per 3 hours
Answer:
12
Explanation:
The coefficient of the CO2 shows the amount of CO2 needed in the reaction so to react with 11 water, 12 molecules of carbon dioxide is needed.
Answer:
Your question is not interpreted very well, but as regards what is observed, SO2 is not the formula for sulfur oxide, the formula for sulfur oxide is SO since the valence used in sulfur would be +2 and oxygen -2 therefore the sum of these valences would be equal to zero, therefore it would be the correct thing considering the true equation as SO
Explanation:
There are also sulfur dioxide, or sulfur trioxide, which is usually used in the formation of tertiary salts such as copper sulfate.
sulfur trioxide and sulfur dioxide are synonymous with sulfate or sulphite
Explanation:
The idea behind using fossils to correlate two land masses was first put into limelight by a British geologist, Williams Smith.
According to the principle of fossil and fauna succession "fossils and fauna succeed one another in a define order".
This implies organisms evolve in predictable manner.
Since we know that certain types of organisms live within a period in time on the earth surface, we expect that such organisms would be fossilized in the geologic record and preserved.
- Identify the fossil record in one part of the land mass. Log the rock types with the corresponding fossils in them.
- On the other side, repeat the same process.
- Look for unconformity surfaces where some part of the stratigraphic records might have been lost.
- If the fossil records on one side corresponds with that on the other other side, it suggests that the land masses must have once been joined together.
- The logic is that when the organism were on the same land mass, they thrived and lived together.
- They became fossilized together till the lands separated.
learn more:
fossils brainly.com/question/9415077
#learnwithBrainly
2.45 °C
From the Ideal gas law (Combined gas law)
PV/T = P'V'/T' .....eq 1
Where:
P - initial pressure
V - initial volume
T - initial temperature
P' - final pressure
V' - final volume
T' - final temperature.
To proceed we have to make T the subject from eq.1
Which is, T = P'V'T/PV.......eq.2
We have been provided with;
Standard temperature and pressure (STP)
P = 760 mm Hg (SP - Standard Pressure)
T = 273.15 K (ST - Standard Temperature)
V = 62.65 L
P' = 612.0 mm Hg
V' = 78.31 L
T' = ? (what we require)
Therefore, we substitute the values into eq.2
T' =
.
T' = 275.60 K
T = (275.60 - 273.15) ......To °C
T = 2.45 °C
>>>>> Answer
Have a nice studies.
