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DIA [1.3K]
3 years ago
15

19)Calculate the number of moles of Al2O3 that are produced when 15 mol of Fe is produced

Chemistry
1 answer:
Margarita [4]3 years ago
6 0

Answer:

C

Explanation:

Calculate the number of moles of Al2O3 that are produced when 15 mol of Fe is produced

in the following reaction.

C) 45 mol

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An unknown liquid has a vapor pressure of 88 mmhg at 45°c and 39 mmhg at 25°c. What is its heat of vaporization?
Elis [28]

The relation between vapour pressure , enthalpy of vapourisation and temperature is

ln(\frac{P1}{P2} ) = \frac{deltaH}{R} (\frac{1}{T2} - \frac{1}{T1})

ln (88/ 39) = DeltaH / 8.314 (1 / 318 - 1 / 298)

0.814 = DeltaH / 8.314 (2.11 X 10^-4 )

DeltaH = -32.07 kJ


6 0
3 years ago
Which statements are true? Check all that apply. Check all that apply. The higher the temperature, the more soluble most ionic s
snow_lady [41]

Answer:

The higher the temperature, the more soluble most ionic solids are in water

As you cool a saturated solution from high temperature to low temperature, solids start to crystallize out of solution if you achieve a supersaturated solution.

If you raise the temperature of a saturated solution, you can (usually) add more solute and make the solution even more concentrated.

Explanation:

For many ionic solids, solubility in water increases with increase in the temperature of the solution.

This implies that increasing the temperature allow more solute to dissolve in the solvent, supersaturation may be achieved by so doing. As the solution is cooled, the solid crystalizes out of solution hence the answers above.

8 0
3 years ago
.......help me please !!
VikaD [51]

Answer:

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Explanation:

7 0
3 years ago
If a dog has a mass of 16.1 kg, what is its mass in the following units? Use scientific notation in all of your answers.
nekit [7.7K]

Answer:

16.1\times 10^3\ \text{g}

16.1\times 10^{6}\ \text{mg}

16.1\times 10^{9}\ \mu\text{g}

Explanation:

Mass of dog = 16.1\ \text{kg}

1\ \text{kg}=10^{3}\ \text{g}

1\ \text{kg}=10^{6}\ \text{mg}

1\ \text{kg}=10^{9}\ \mu\text{g}

So,

16.1\ \text{kg}=16.1\times 10^3\ \text{g}

16.1\ \text{kg}=16.1\times 10^{6}\ \text{mg}

16.1\ \text{kg}=16.1\times 10^{9}\ \mu\text{g}

Mass of the dog in the other units is 16.1\times 10^3\ \text{g}, 16.1\times 10^{6}\ \text{mg} and 16.1\times 10^{9}\ \mu\text{g}.

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3 years ago
What decides the pitch of sound
dmitriy555 [2]
The vibration objects
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3 years ago
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