B,c hop you git a good grad
The equation to calculate Density is Mass / Volume. You are given that the density is 5.45 and the mass is 65; 5.45 = 65 / v. So v = 65 / 5.45; v = 11.93 mL (or if you want your answer to consider significant figures, v = 12 mL).
0.29 M ammonia + 0.38 M ammonium bromide and 0.22 M hypochlorous acid + 0.18 M hydroiodic acids of aqueous solutions are good buffer systems.
<h3>Buffer Systems:</h3>
A solution that resists pH change when acids or bases are added to it is referred to as a buffer system. Either a weak acid and its salt, or a weak base and its salt, make up buffer systems. The ratio of HX/X- does not considerably alter when an acid or a base is introduced to a buffer.
Solutions known as buffers withstand pH changes when an acid or base is added. A weak base (A) and its conjugate weak acid (HA) are both present in buffers. When a reactive system is in equilibrium, adding a strong electrolyte with one common ion will cause the equilibrium to shift, lowering the concentration of the common ion. Buffers differ from one another in terms of pH range and buffer capacity.
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No It is not correct.
Correct oxidation number of hydrogen in NaH,H2 and H2S are:
- Let x be the Oxidation state of ’H’ by oxidation state rule.
x+1 =0 (Sodium has +1 Oxidation state )
x=−1
Therefore, -1 is oxidation number of Hydrogen in NaH.
- The oxidation number of an element's atom in its standard state is zero. As a result, the oxidation number for H2 is zero.
- The hydrogen oxidation number in H2 is +1. As a result, that hydrogen atom can be reduced to lower oxidation states of hydrogen, such as 0 and -1. However, because +1 is the highest oxidation state of hydrogen, the hydrogen atom cannot be reduced any further.
<h3>What is oxidation number?</h3>
In simple terms, the oxidation number is the number assigned to elements in a chemical combination. The oxidation number is the number of electrons that atoms in a molecule can share, lose, or gain when forming chemical bonds with atoms of a different element.
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