Answer:
Higher than 59 °C because dipole-dipole interactions in iodine monochloride are stronger than dispersion forces in bromine.
Explanation:
I just took the test and i got it right
First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2 so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄ ⇄ H⁺ + HC₂O₄⁻
0.0356 M 0 0
0.0356 - x x x
Ka1 =
![\frac{[H^+][HC2O4^-]}{[H2C2O4]}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BH%5E%2B%5D%5BHC2O4%5E-%5D%7D%7B%5BH2C2O4%5D%7D%20)
= x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6
Answer:
The left and right hemispheres of the cerebrum are connected by the Corpus Collosum.
Explanation:
The corpus collosum is a thick band of neurons that divides the cerebral cortex lobes into the left and right hemisphere. The corpus callosum allows for both hemispheres to communicate and transfer information! The primary function of the corpus callosum is to integrate sensory, motor, and cognitive performance between the cerebral cortex.
Ins severe cases of epileptic seizures, a corpus callosotomy is performed, which cuts the corpus callosum in half. This prevents the seizures from becoming more severe, and the brain can reprogram, through neuroplasticity.
Answer:B, the colloid particles are larger.
PLEASE GIVE BRAINLIEST AND WATCH OUT BEHIND YOU
Answer:
a theory of a experiment and the experiment acts like a judge determining if the hypothesis is right or wrong from the final test result
Explanation: