Answer:
1000m2 / s2
Explanation:
Hello! In order to verify this, we have to do unit conversion. We also have to know that J (Joule) = kg * m2 / s2
Then we can start with the test.
1kJ / kg * (1000J / 1kJ) = 1000J / kg
1000J / kg = 1000kg * m2 / kg * s2
In this step we can simplify "kg".
So the result is
1000m2 / s2
The answers tot the question above is amplitude
The electrons that are in the outermost electron shell, also known as the valence shell, have more energy then those in the inner electron shells, I hope this helps<3
Answer:
oxidizer
Explanation:
an example of an oxidizers are oxygen and hydrogen peroxide
The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal
How to determine the mole of glucose
Mass of glucose = 49 g
Molar mass of glucose = 180.2 g/mol
Mole of glucose = ?
Mole = mass / molar mass
Mole of glucose = 49 / 180.2
Mole of glucose = 0.272 mole
How to determine the energy released
C₆H₁₂O₆ →2C₂H₆O + 2CO₂ ΔH = -16 kcal/mol
From the balanced equation above,
1 mole of glucose released -16 kcal of energy
Therefore,
0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal
Thus, -4.4 Kcal were released from the reaction
Learn more about stoichiometry:
brainly.com/question/14735801
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