Answer:
Check explanation.
Explanation:
Reductive amination is also known as reductive alkylation. Reductive amination is an good chemical reaction for the conversion of of carbonyl group into amine.
These are the steps to follow for the reaction;
(1). Step one: carbonyl group(either an aldehyde or a ketone) is used to convert amine to form an imine. The pH of the reaction should be slightly acidic.
(2). Step 2: the imine from step one is then converted into iminium ion under acidic condition too(for protonation).
(3). Step 3: the iminium ion is then reduced to the amine.
The equation of reaction are in the attached file.
Note: the attached picture is labelled (A) to (D).
Reaction A is the reaction of benzaldehyde with Benzylamine, B is the reaction of benzaldehyde with dibenzylamine, C is the reaction of benzaldehyde with N,N-Dimethylbenzylamine and D is the reaction of benzaldehyde with N-Benzylpiperidine.
Answer:
I kinda forgot. I'm sorry if I didn't answer your question.
Explanation:
Answer:
Ionic Exergonic
Explanation:
Exergonic reactions have negative Gibbs free energy and hence are spontaneous.
Endergonic reactions have negative Gibbs free energy and are non-spontaneous and low temperature.
Endergonic reactions require external supply of energy. But such reactions can be made spontaneous or favorable by coupling with exergonic reaction via a common intermediate.
Therefore, the correct answer is Ionic Exergonic.
Answer:
17.76g
Explanation:
We need to write a balanced chemical equation for the reaction:
2Al(OH)3 + 3Ca(NO3)2 ——> 3Ca(OH)2 + 2Al(NO3)3
In the reaction above, it can be seen that 2 moles of aluminum hydroxide yielded 3 moles of calcium hydroxide. This is the theoretical viewpoint.
Now we need to know what actually happened. We need to calculate the actual number of moles of aluminum hydroxide reacted l. We can get this by dividing the mass by the molar mass.
The molar mass of aluminum hydroxide is 27+ 3( 16+1)
= 27 + 51 = 78g/mol
The number of moles is thus: 12.55/78 = 0.16 moles
Now if 2 moles of aluminum hydroxide gave 3 moles of calcium hydroxide, 0.16moles will give : (0.16*3)/2 = 0.24moles
Now we can calculate the mass of calcium hydroxide formed. The mass of calcium hydroxide formed is the number of moles multiplied by the molar mass.
The molar mass of calcium hydroxide is; 40 + 2(17) = 74g/mol
The mass is thus =74 * 0.24 = 17.76g
