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Viktor [21]
3 years ago
13

A student runs an experiment in the lab and then uses the data to prepare an Arrhenius plot of the natural log of the rate const

ant (ln k) versus the inverse of the absolute temperature (1 / T). The general equation of the resulting line is given below. What is the activation energy for the reaction in kilojoules per mole? y = - 2.63 × 103 x + 27.3

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

21.86582KJ

Explanation:

The graphical form of the Arrhenius equation is shown on the image attached. Remember that in the Arrhenius equation, we plot the rate constant against the inverse of temperature. The slope of this graph is the activation energy and its y intercept is the frequency factor.

Applying the equation if a straight line, y=mx +c, and comparing the given equation with the graphical form of the Arrhenius equation shown in the image attached, we obtain the activation energy of the reaction as shown.

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shtirl [24]
A mass of protons and neutrons. Hope this helps. Abby (I'm really awesome)
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4 years ago
The following equation shows the equilibrium in an aqueous solution of ammonia:NH3(aq)+H2O(l)⇌NH4+(aq)+OH−(aq)Which of the follo
victus00 [196]

Answer:

OH⁻ and H₂O

Explanation:

From the equation given in question ,

NH₃ (aq) + H₂O (l) ⇌ NH₄⁺ (aq) + OH⁻ (aq)

Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.

When an acid donates a proton, it changes into a base which is known as its conjugate base.

Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.

The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.

Hence , from the equation given in the question ,

The conjugate acid - base pair is -

OH⁻ and H₂O

4 0
3 years ago
A gas has a pressure of 851mmHg at 330.K. What will its temperature be at 990.mmHg?
aev [14]

Answer:

383.90K

Explanation:

P1 = 851mmHg

T1 = 330K

T2 = ?

P2 = 990mmHg

To solve for P2, we have to use pressure law which states that the pressure of a fixed mass of fixed is directly proportional to its temperature provided that volume remains constant

Mathematically,

P = kT, k = P/T

P1 / T1 = P2 / T2 = P3 / T3 =.......=Pn / Tn

P1 / T1 = P2 / T2

T2 = (P2 × T1) / P1

T2 = (990 × 330) / 851

T2 = 383.90K

The final temperature of the gas is 383.90K

3 0
4 years ago
5 points
podryga [215]

Answer:

the answer would be A have good day

Explanation:

pls mark brainliest and 5 stars

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7 0
3 years ago
Chlorine has two naturally occurring isotopes, ³⁵Cl and ³⁷Cl. What is the mass number of each isotope? How many protons, neutron
Arte-miy333 [17]

The mass number of ³⁵Cl and ³⁷Cl is 35 and respectively.

<h3>What is atomic mass? </h3>

Atomic mass is defined as the sum of number of protons and number of neutrons of an element.

Atomic mass is represented by A.

<h3>What is Atomic number?</h3>

Atomic number is defined as the number of electron in an element.

Atomic number is represented by Z.

<h3>What is Isotopes? </h3>

Isotopes are the element which have same atomic number but have different atomic mass.

Number of proton is equal to number of electrons.

Proton is positively charged, electrons are negativity charge while neutrons are neutral in nature.

Proton and neutrons are present in the nucleus of an element. On the other hand, electron revolves around the nucleus.

The atomic number of ³⁵Cl and ³⁷Cl is 17.

Number of protons = Number of electrons = 18.

Neutrons = atomic mass - atomic number

Neutrons of ³⁵Cl = 35-17 = 18

Neutrons of ³⁷Cl= 37- 17= 20

So, they have different atomic mass and number of neutrons.

Thus, we concluded that the mass number of ³⁵Cl and ³⁷Cl is 35 and 37 respectively.

learn more about atomic mass:

brainly.com/question/14250653

#SPJ4

6 0
2 years ago
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