<span>"Increased energy use leads to increased economic activity and an increased quality of life. Ever since the industrial revolution, advances in technology have let humans in industrialized nations increase their standard of living significantly, which required significant increases in the amount of energy harnessed per capita."
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The answer would be D. (The 4th one listed).
Abiotic factors are the non-living parts of the environment that can often have a major influence on living organisms.
Hope this helps!
<span>Answer: 0.00 meters
Solution:
Step 1: Define displacement
DISPLACEMENT = a vector quantity that describes "linear or angular distance in a given direction between a body or point and a reference position."
Step 2: Understand the question
Assumption 1: Assume that when the ant moves 4.25 meters from its origin to its nest, it is moving in a positive direction (on a graph you would draw a line along the x-axis from its origin to +4.25).
Assumption 2: Assume that when the ant "turns around...back to the source of food", it is moving back in the negative direction (towards the origin).
Step 3: Analyze the question
What is the distance between where the ant originally started and where it ended its journey?
The ant started and ended its journey in the same place.
While it traveled a distance of 8.52 meters (2 * 4.26 = 8.52), it's displacement is actually 0.00 meters (4.26 + (-4.26) = 0.00)
Therefore, the answer is 0.00 meters</span>
Answer:
The value of the activation energy is 240.96 kJ/mol.
Explanation:
According to the Arrhenius equation,
The graph between log(k) and (1/T) will give straight line with negative slope along with the intercept corresponding to the value of A.
Slope f the line =
The slope of the line :
The value of the activation energy is 240.96 kJ/mol.
Mass of K = 39.1g/mole
Mass of H = 1g/mole
Mass of C = 12g/mole
Mass of O = 16g/mole
Mass of KHCO3 = 39.1 + 1 + 12 + 3*16 = 100,1g/mole
100% ------------ 100.1g of KHCO3
x% ----------------- 12g of C
x = 11,99% of C in KHCO3
100% -------------- 100.1 of KHCO3
y% --------------------3*16g of O
y = 47,95% of O in KHCO3
100% ------------- 100.1g of KHCO3
z% ---------------- 1g of H
z = 0,99% of H in KHCO3
11,99% + 47,95% + 0,99% = 60,93% ≈ 61%
<u>answer: C</u>