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solniwko [45]
3 years ago
14

A compound consists of 81.8% C and 18.2% H by mass. What is its empirical formula?​

Chemistry
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

Empirical formula of 81.8 carbon and 18.2 hydrogen

Steps

  • Find the empirical formula of a compound that has 81.8% of Carbon (C), 18.2% of Hydrogen (H).
  • Divide by fractional component of each mole value: C=1.5354936431103, H=4.0709872862205Round to closest whole numbers: C=2, H=4
<h3> Combine to get the empirical formula: C2H4</h3>

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Answer:

The answer to your question is below

Explanation:

Propane = C₃H₈

Process

1.- Write the chemical reaction

                     C₃H₈  +  O₂   ⇒   CO₂  +  H₂O

balanced chemical reaction

                      C₃H₈  +  5O₂   ⇒  3CO₂  +  4H₂O

               Reactants      Elements     Products

                      3                    C                  3

                      8                    H                  8

                     10                    O                 10

b) Standard enthalpy

Propane                  -104.7 kJ/mol

Oxygen                         0   kJ/mol

Carbon dioxide      -393.5 kJ/mol

Water                      -241.8 kJ/mol

ΔH° = ∑ΔH° products - ∑H° reactants

ΔH° = 3(-393.5) + 4(-241.8) - [(-104.7) + 0]

-Simplification

ΔH° = -1180.5 kJ/mol - 967.2 kJ/mol + 104.7 kJ/mol

ΔH° = - 2042.5 kJ/mol

This reaction is exothermic because ΔH° is negative.

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