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gavmur [86]
2 years ago
12

The reaction is run at two temperatures where temperature 1 is lower than temperature 2. Which relationship is correct for eithe

r rate constant (k1 or k2) or activation energy (Ea,1 and Ea,2)
Chemistry
1 answer:
Tasya [4]2 years ago
8 0

Answer:

The answer is "K_1 < K_2"

Explanation:

In the given question, the value of the K=Ae^{-\frac{Ea}{RT}} and the T_1is the rate value which is the constant that is  K_2>K_1. As per the temperature value when its increase rate is constantly increasing. E_a is activation energy it is not dependent on the temperature that why the answer is K_1 < K_2.

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