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Paul [167]
3 years ago
7

For a wind farm to be effective, it needs to be in a place with what kind of wind?

Chemistry
2 answers:
Ronch [10]3 years ago
8 0

Answer:

High average speeds

Explanation:

I took the test lol

sladkih [1.3K]3 years ago
3 0

Answer: high average wind speeds

Explanation: I found out the hard way

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Methane gas is produced from the reaction of solid carbon and hydrogen gas: C(s)+2H2(g)→CH4(g) . How many liters of hydrogen gas
Stels [109]

Answer:

80 liters

Explanation:

At STP, 1 mole of ideal gas has a volume of 22.4 liters.

Therefore, since liters and moles are directly proportional, we can use stoichiometry directly.

40L CH₄ × (2L H₂ / 1L CH₄) = 80L H₂

7 0
3 years ago
Plz help me and I promise I will make you he brainiest
a_sh-v [17]

Answer:

2

Explanation:

1 is definitely wrong

density must be lower to atop another liquid

in 3 ,I consider the example of water and oil whi has a lower boiling point

6 0
3 years ago
How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)
nikdorinn [45]

You can solve this problem through dimensional analysis.

First, find the molar mass of NaHCO3.

Na = 22.99 g

H = 1.008 g

C = 12.01 g

O (3) = 16 (3) g

Now, add them all together, you end with with the molar mass of NaHCO3.

22.99 + 1.008 + 12.01 + 16(3) = 84.008 g NaHCO3. This number means that for every mole of NaHCO3, there is 84.008 g NaHCO3. In simpler terms, 1 mole NaHCO3 = 84.008 g NaHCO3.

After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.

200. g NaHCO_3 * \frac{1 mole NaHCO_3}{84.008 g NaHCO_3}

Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3

200.  * 1 = 200

200/ 84.008 = 2.38

Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.

Your final answer is 2.38 mol NaHCO3.

8 0
3 years ago
ASAP PLLEEASE HURYYYYYYYYYYRRRRRRRRRRRRYY (NO FILES FOR ME NEEDING TO DOWNLAOD PLEASE!)
pickupchik [31]

Answer:

1.Fill in the blank with the correct term to make the statement true.

During the (night)

at the beach, the land cools down

(slower)

than the

(ocean).

Because of this, the air over the land is

(Warmer) than the air over the ocean. The

(More)

dense air rises over the ocean and the cooler,

(More)

dense air blows in from over the land creating a

(sea)

breeze.

2.Which statement is true about winds?

Winds always blow from low to high pressure.

true

Winds always blow from water to land.

false

Winds always blow from land to water.

false

3. Winds always blow from high to low pressure. How do landmasses impact the movement of air and water?

They stop all movement of both air and water.

They speed up the air and water and allow it to pass though.

They change the direction and slow them down.

think this is it

They slow down the air but speed up the water.

pt:2

answering the pictures

9- I don know sorry

15-B

16-A

Explanation:

just trying to help LET ME KNOW IF IT'S WORNG

3 0
3 years ago
Read 2 more answers
If the molar heat of combustion of liquid benzene at constant volume and 300k is -3272KJ. Calculate the heat of combustion at co
vladimir2022 [97]

Answer:

The heat at constant pressure is -3,275.7413 kJ

Explanation:

The combustion equation is 2C₆H₆ (l) + 15O₂ (g)  → 12CO₂ (g) + 6H₂O (l)

\Delta n_g = (12 - 15)/2 = -3/2

We have;

\Delta H = \Delta U + \Delta n_g\cdot R\cdot T

Where R and T are constant, and ΔU is given we can write the relationship as follows;

H = U + \Delta n_g\cdot R\cdot T

Where;

H = The heat at constant pressure

U = The heat at constant volume = -3,272 kJ

\Delta n_g = The change in the number of gas molecules per mole

R = The universal gas constant = 8.314 J/(mol·K)

T = The temperature = 300 K

Therefore, we get;

H = -3,272 kJ + (-3/2) mol ×8.314 J/(mol·K) ×300 K) × 1 kJ/(1000 J) = -3,275.7413 kJ

The heat at constant pressure, H = -3,275.7413 kJ.

4 0
3 years ago
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