Equation of bhr and h2o

Luciana explains to Eric how electricity flows in a circuit. Which sentences are a part of her explanation? Select all that appl

Flauer [41]

I’m pretty sure it c hope that helped

8 0

3 years ago

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Calculate the volume of dry co2 produced at body temperature (37 ∘c) and 0.970 atm when 25.5 g of glucose is consumed in this re

katrin2010 [14]

I believe the balanced chemical equation is:

C6H12O6 (aq) + 6O2(g) ------> 6CO2(g) + 6H2O(l)

First calculate the moles of CO2 produced:

moles CO2 = 25.5 g C6H12O6 * (1 mol C6H12O6 / 180.15 g) * (6 mol CO2 / 1 mol C6H12O6)

moles CO2 = 0.8493 mol

Using PV = nRT from the ideal gas law:

V = nRT / P

V = 0.8493 mol * 0.08205746 L atm / mol K * (37 + 273.15 K) / 0.970 atm

V = 22.28 L

6 0

3 years ago

What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The

Effectus [21]

Answer: The energy released in the given nuclear reaction is 1.3106 MeV.

Explanation:

For the given nuclear reaction:

$_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}$

We are given:

Mass of $_{19}^{40}\textrm{K}$ = 39.963998 u

Mass of $_{20}^{40}\textrm{Ca}$ = 39.962591 u

To calculate the mass defect, we use the equation:

$\Delta m=\text{Mass of reactants}-\text{Mass of products}$

Putting values in above equation, we get:

$\Delta m=(39.963998-39.962591)=0.001407u$

To calculate the energy released, we use the equation:

$E=\Delta mc^2\\E=(0.001407u)\times c^2$

$E=(0.001407u)\times (931.5MeV)$ (Conversion factor: $1u=931.5MeV/c^2$ )

$E=1.3106MeV$

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0

3 years ago

Can someone who expert in chemistry be my personal tutor? I'm so desperate

lions [1.4K]

Yes..? I don’t understand what you’re trying to ask mate.

5 0

3 years ago

Why do some atoms form positive ions and others form negative ions?

Scrat [10]

It is energetically favorable for all atoms to have a complete outer electron shell. Loosely, the atoms on the left hand side of the periodic table only have a few extra electrons in their outer shell so it is energetically favorable for them to lose them. The atoms on the right hand side of the periodic table almost have enough electrons in their outer shell and so they have a tendency to gain them. Once electrons have left an electron shell, an atom will have a positive charge because it has more protons (positive charges) than electrons (negative charges). Similarly, an electron which has gained electrons to complete its outer shell will have a negative charge because it now has more electrons (negative charge) than protons (positive charge).

8 0

3 years ago