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aliya0001 [1]
2 years ago
11

Schopenhauer thought that treating others with compassion was one of the few ways to make the world better.

Physics
1 answer:
andriy [413]2 years ago
6 0
I believe it’s false, I think I had this before
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Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
shtirl [24]

Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m

Explicación:

Dado lo siguiente:

Altura desde la cual se cae el cuerpo = 120 m

Tiempo (t) = 2.5s

A.) La velocidad que toma:

El cuerpo cayó desde una altura;

velocidad inicial (u) = 0

Para calcular v:

V = u + en

Donde a = aceleración debido a la gravedad = 9.8m / s

v = 0 + (9.8) (2.5)

v = 24.5 m / s

B) Cuánto ha disminuido.

Usando la ecuación de movimiento:

S = ut + 0.5at ^ 2

Donde S = distancia

S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)

S = 0 + 0.5 (9.8) (6.25)

S = 30.625 m

Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m

C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m

5 0
3 years ago
Nancy ran a distance of 5km in 30 minutes. What is her speed in meters(m) per hour)h)
Virty [35]

The speed of Nancy who ran a distance of 5 km in 30 minutes is 10000 meters(m) per hour(h).

<h3>What is the rate of speed?</h3>

The rate of speed is the rate at which the total distance is travelled in the time taken. Rate of speed can be given as,

s=\dfrac{d}{t}

Here, (d) is the distance travelled by the object and (t) is the time taken but the object to cover that distance.

Nancy ran a distance of 5 km in 30 minutes. There are 60 minutes in one hour. Thus, the time in hour for which Nancy ran is,

t=\dfrac{30}{60}\\t=0.5\rm\; hr

The meters in 5 kilometers is,

d=5\times1000\\d=5000\rm\; m

She ran 5000 kilometers in 0.5 hours. Thus, the speed of her is,

s=\dfrac{5000}{0.5}\\s=10000\rm\; km/hr

Thus, the speed of Nancy who ran a distance of 5 km in 30 minutes is 10000 meters(m) per hour(h).

Learn more about the rate of speed here:

brainly.com/question/359790

#SPJ4

7 0
2 years ago
A sound wave has a wavelength of 15 meters with a frequency of 2.5 Hz. What would the velocity be for this situation in
rodikova [14]

Answer:

6m/s

Explanation:

V = frequency * wavelength

15 * 2.5 = 6m/s

7 0
2 years ago
A body moving at .500c with respect to an observer
lakkis [162]

Answer:

0.8c and -0.14c

Explanation:

The first fragment will have a speed of +0.5c respect of a frame of reference moving at +0.5c

Lest name v the velocity of the frame of reference, and u' the velocity of the object respect of this moving frame of reference.

The Lorentz transform for velocity is:

u = (u' + v) / (1 + (u' * v) / c^2)

u = (0.5c + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = 0.8c

The other fragment has a velocity of u' = -0.6c respect of the moving frame of reference.

u = (-0.6v + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = -0.14c

6 0
2 years ago
Most of the currents identified have a circular shape. This is because as the air and water move between the equator to the pole
Morgarella [4.7K]
I believe it is true . Somebody correct me if I’m wrong!
5 0
2 years ago
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