1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
storchak [24]
3 years ago
13

Earth's atmosphere is made up of mostly nitrogen (78%) and oxygen (21%); however, there are other gases in smaller amounts, like

argon, carbon dioxide, neon, helium, hydrogen, and more. If there was an increase of carbon dioxide in the atmosphere, how would this affect temperature? A) The temperature would increase globally. B) The temperature would decrease globally. C) Temperature doesn't relate to the composition of the atmosphere; it has to do with the sun's rays. D) The temperature would not be affected since carbon dioxide is only one component in the atmosphere.
Physics
2 answers:
pishuonlain [190]3 years ago
5 0

Answer:

the temperature would increase globally because carbon dioxde contributes to global warming increase the temperature of the earth

Explanation:

i hope this will help you

tatiyna3 years ago
3 0

Answer:

a

Explanation:

You might be interested in
ANYONE who is good with the consequences of Population growth PLEASE help me!!
alekssr [168]

in china, there is a family limit for only having 1 child

at 10 billion people on earth, we will most likely run out of food supply

4 0
3 years ago
Read 2 more answers
3. A football is kicked with a speed of 35 m/s at an angle of 40°.
jarptica [38.1K]

a) 22.5 m/s

The initial vertical velocity is given by:

u_y = u sin \theta

where

u = 35 m/s is the initial speed

\theta=40^{\circ} is the angle of projection of the ball

Substituting into the equation, we find

u_y = (35)(sin 40)=22.5 m/s

b) 26.8 m/s

The initial horizontal velocity is given by:

u_x = u cos \theta

where

u = 35 m/s is the initial speed

\theta=40^{\circ} is the angle of projection of the ball

Substituting into the equation, we find

u_x = (35)(cos 40)=26.8 m/s

c) 2.30 s

The time it takes for the ball to reach the maximum heigth can be found by considering the vertical motion only. This is a uniformly accelerated motion (free-fall), so we can use the suvat equation

v_y = u_y + at

where

v_y is the vertical velocity at time t

u_y = 22.5 m/s

a=g=-9.8 m/s^2 is the acceleration of gravity (negative because it is downward)

At the maximum height, the vertical velocity becomes zero, v_y =0; substituting, we find the time t at which this happens:

0=u_y + gt\\t=-\frac{u_y}{g}=-\frac{22.5}{-9.8}=2.30 s

d) 25.8 m

The maximum height can also be found by considering the vertical motion only. We can use the following suvat equation:

s=u_y t + \frac{1}{2}gt^2

where

s is the vertical displacement at time t

u_y = 22.5 m/s

g=-9.8 m/s^2

Substituting t = 2.30 s, we find the displacement at maximum height, so the maximum height:

s=(22.5)(2.30)+\frac{1}{2}(-9.8)(2.30)^2=25.8 m

e) 123.3 m

In order to find how far does the ball lands, we have to consider the horizontal motion.

First of all, the time it takes for the ball to go back to the ground is twice the time needed for reaching the maximum height:

t=2(2.30 s)=4.60 s

Then, we consider the horizontal motion. There is no acceleration along this direction, so the horizontal velocity is constant:

v_x = 26.8 m/s

Therefore, the horizontal distance travelled during the whole motion is

d=v_x t = (26.8)(4.60)=123.3 m

So, the ball lands 123.3 m far from the initial point.

4 0
3 years ago
If a dog runs 25m east and then turns around and runs
Nostrana [21]

Answer:

The dog ran a total distance of 45m but he is only 5m away from the starting line

Explanation: When you add 25 to 20 you get 45 for the total distance and if he ran back in the same direction then you would subtract 20 from 25 and get 5m

8 0
3 years ago
A bus accelerates forward. If an apple were on the floor of the bus it would move forward.
Paladinen [302]

Answer:

False

Explanation:

Since it is on the bus, it would not move forward because the outside acceleration cannot be considered.

4 0
3 years ago
Define the term antinode and explain how standing waves form.
Otrada [13]

Answer:

standing wave, also called stationary wave, combination of two waves moving in opposite directions, each having the same amplitude and frequency.

For oppositely moving waves, interference produces an oscillating wave fixed in space. fixed nodes in a standing wave. Location of fixed nodes in a standing wave

these are the points that undergo the maximum displacement during each vibrational cycle of the standing wave. In a sense, these points are the opposite of nodes, and so they are called antinodes. A standing wave pattern always consists of an alternating pattern of nodes and antinodes

Explanation:

6 0
3 years ago
Other questions:
  • Two identical space probes are orbiting Jupiter. Scientists determine that one of the space probes has a larger gravitational fo
    12·2 answers
  • Who invented the transistor
    5·2 answers
  • Which pair below describes isotopes of the same element? A) an atom with 6 protons and 8 neutrons - an atom with 8 protons and 6
    14·2 answers
  • Sinusoidal water waves are generated in a large ripple tank. The waves travel at 20 cm/s and their adjacent crests are 5.0 cm ap
    13·1 answer
  • The force between a 100 kg man and the Earth is 980 N. How close must two protons (1.6 X 10-19 C) be to generate the same force?
    13·1 answer
  • A golfer hits her tee-shot due north towards the fairway. Her shot has an initial velocity of 60 m/s. A 15 m/s wind is blowing i
    9·1 answer
  • With what speed must a ball be thrown directly upward so that it remains in the air for 10 seconds?
    13·1 answer
  • Can u pls help me ........
    9·1 answer
  • PLEASE ASSIST 20 POINTS
    10·1 answer
  • A flat metal washer is heated. As the washer's temperature increases. What happens to the hole in the center?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!