The compression curve would be theoretically given for a system of bodies in which the spring applies the force (Although in the same way the following process can be extrapolated to any system, depending on the type of Force to consider) For a spring mass system, the strength is given by Hooke's law as

Where,
K = Spring constant
x = Displacement
If we integrate based on distance we would have

This integral represents the area under the Force Curve based on each distance segment traveled.



This is the same formula that represents the elastic potential energy of a body. Therefore the correct answer is D.
(a) The maximum potential difference across the resistor is 339.41 V.
(b) The maximum current through the resistor is 0.23 A.
(c) The rms current through the resistor is 0.16 A.
(d) The average power dissipated by the resistor is 38.4 W.
<h3>Maximum potential difference</h3>
Vrms = 0.7071V₀
where;
V₀ = Vrms/0.7071
V₀ = 240/0.7071
V₀ = 339.41 V
<h3> rms current through the resistor </h3>
I(rms) = V(rms)/R
I(rms) = (240)/(1,540)
I(rms) = 0.16 A
<h3>maximum current through the resistor </h3>
I₀ = I(rms)/0.7071
I₀ = (0.16)/0.7071
I₀ = 0.23 A
<h3> Average power dissipated by the resistor</h3>
P = I(rms) x V(rms)
P = 0.16 x 240
P = 38.4 W
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The potential energy of the block is A) 490 J
Explanation:
The potential energy of an object is the energy possessed by the object due to its position in the gravitational field.
It is calculated as follows:

where
m is the mass of the object
g is the acceleration due to gravity
h is the height of the object above the ground
For the block in this problem, we have:
m = 10 kg

h = 5 m
Therefore, its potential energy is:

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Answer:
1. Primary or P waves are push and pull waves
2. Secondary, S or Shear Waves are also called transverse wave
3. L or surface waves reach the earth's surface after P and S waves
-- volume = (length)(width)(height)
-- Since the cube is a cube, its three dimensions are all the same number.
Volume = (2.5cm)(2.5cm)(2.5cm)
Volume = 15.625 cubic cm
-- density = (mass) / (volume)
Density = (1129.56g) / (15.625cm^3)
Density = 72.3 g/cm^3
(roughly 3.2 TIMES the density of the most dense naturally occurring substance on Earth)