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3 years ago

How do organisms interact with each other?

Physics

1 answer:

satela [25.4K]3 years ago

6 0

Answer:

They interact in a lot of ways, prey, predator, etc.

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A sprinter is running the 100 meter dash at a speed of 24 m/s. How long does it the sprinter to finish?

DerKrebs [107]

Answer:

4.1666666 seconds

Explanation:

100 divided by 24 will give you about 4.1666666 seconds or 4 1/6 seconds. Hope it helps!

6 0

3 years ago

Which explains how the ocean warms the air? A. The seawater absorbs heat from the sun and warms the air above it by convection.

mr Goodwill [35]

The right answer is c because it absorbs the heat then it pushes it away like radiation

6 0

3 years ago

Read 2 more answers

You are at the controls of a particle accelerator, sending a beam of 2.10×107 m/s protons (mass m) at a gas target of an unknown

Kipish [7]

Answer:

The mass is $m_2 =21.75*10^{-27} \ kg$

The velocity is $v_2 = 3.0*10^{6} m/s$

Explanation:

From the question we are told that

The speed of the protons is $u_1 = 2.10*10^{7} m/s$

The mass of the protons is $m$

The speed of the rebounding protons are $v_1 = -1.80 * 10^{7} \ m/s$

The negative sign shows that it is moving in the opposite direction

Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as

$m_2 = [\frac{u_1 -v_1}{u_1 + v_1} ] m_1$

Where $m_1$ is the mass of a single proton

So substituting values

$m_2 = \frac{2.10 *10^{7} - (-1.80 *10^{7})} {(2.10 *10^7) + (-1.80 *10^{7})} m_1$

$m_2 =13 m_1$

The mass of on proton is $m_1 = 1.673 * 10^{-27} \ kg$

So $m_2 =13 ( 1.673 * 10^{-27} )$

$m_2 =21.75*10^{-27} \ kg$

Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as

$m_1 u_1 + m_2u_2 = m_1 v_1 + m_2v_2$

Now $u_2$ because before collision the the nucleus was at rest

$m_1 u_1 = m_1 v_1 + m_2v_2$

=> $v_2 = \frac{m_1(u_1 -v_1)}{m_2}$

Recall that $m_2 =13 m_1$

$v_2 = \frac{m_1(u_1 -v_1)}{13m_1}$

=> $v_2 = \frac{(u_1 -v_1)}{13}$

substituting values

$v_2 = \frac{( 2.10*10^{7} -(-1.80 *10^{7}))}{13}$

$v_2 = 3.0*10^{6} m/s$

7 0

3 years ago

What is the potential energy of a 0.5 kg object sitting on a shelf that is 1.5 meters high?

Archy [21]

Gravitational potential energy=mass x height X gravitational field strength
=0.5 x1.5 x9.7(gravity)=7.275J

5 0

3 years ago

Read 2 more answers

When liquid water gets into cracks of rock and freezes, it __ and ___.

hoa [83]

It expands and pushes the crack further aprt

3 0

2 years ago

Read 2 more answers