The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²
<h3>Circular motion</h3>
From the question, we are to determine the magnitude of the centripetal acceleration.
Centripetal acceleration can be calculated by using the formula
Where 
is the centripetal acceleration
is the velocity
and 
is the radius
From the given information
and 
Therefore,
Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²
Learn more on circular motion here: brainly.com/question/20905151
Answer:
Your answer will be 6.0kg•m/s
Explanation:
In the given question all the required details d given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.We know the equation of finding momentum asMomentum = mass * velocity = 5 * 1.2 = 6So the momentum of the object is 6 Newton.
Answer:
7 orbitals are allowed in a sub shell if the angular momentum quantum number for electrons in that sub shell is 3.
Explanation:
We that different values of m for a given l provide the total number of ways in which a given s, p,d and f sub shells in presence of magnetic field can be arranged in space along x, y ,z- axis or total number of orbitals into which a given subshell can be divided.
Range for given l lies between -l to +l .
The possible values of m are -3 , -2 , -1 , 0 , 1 ,2 , 3 .
Total number of orbitals are 7.
Answer:
277.78 hours
Explanation:
The formula for calculating the amount of charge is expressed as;
Q = It
I is the current
t is the time
Given
I =0.05A
Q = 50,000C
Required
Time t
Recall that: Q = It
t = Q/I
t = 50,000/0.05
t = 1,000,000secs
Convert to hours
1,000,000secs = 1,000,000/3600
1,000,000secs = 277.78 hours
Hence it will take 277.78 hours for the charge to flow through the diode
