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3 years ago

8. What is the weight in newtons of a 10 kg mass on the earth's surface?

Physics

1 answer:

iogann1982 [59]3 years ago

7 0

Weight = Mass times Acceleration due to gravity.

Weight = 10 kg times 9.8 m/s^2

Weight = 98 kg

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A square wire, 20 cm on the side, moves at constant speed parallel to the xy-plane into a region where there is a uniform magnet

Amanda [17]

Answer:

The speed of the wire is 5 m/s.

Explanation:

Given that,

Length = 20 cm

Magnetic field = 0.1 T

Current = 10 mA

Resistance $R= 10\Omega$

We need to calculate the speed of the wire

Using formula of emf

$\epsilon=Bvl$

Using formula of current

$I=\dfrac{\epsilon}{R}$

Put the value of $\epsilon$ into the formula of current

$I=\dfrac{Bvl}{R}$

$v=\dfrac{IR}{Bl}$

$v=\dfrac{10\times10^{-3}\times10}{0.1\times20\times10^{-2}}$

$v= 5\ m/s$

Hence, The speed of the wire is 5 m/s.

6 0

3 years ago

Choose the word that best completes each sentence.

Igoryamba

Answer:

1.) Tropisms

2.) Thigmotropism

3.) Phototropism

4 0

3 years ago

Read 2 more answers

(a) Write an equation describing a sinusoidal transverse wave traveling on a cord in the positive of a y axis with an angular wa

Vedmedyk [2.9K]

Missing data: the wave number

$k=60 cm^{-1}$

(a) $z = 0.003 sin (6000y-31.4 t)$

For a transverse wave travelling in the positive y-direction and with vibration along the z-direction, the equation of the wave is

$z = A sin (ky-\omega t)$

where

A is the amplitude of the wave

k is the wave number

$\omega$ is the angular frequency

t is the time

In this situation:

A = 3.0 mm = 0.003 m is the amplitude

$k = 60 cm^{-1} = 6000 m^{-1}$ is the wave number

$T = 0.20 s$ is the period, so the angular frequency is

$\omega=\frac{2\pi}{T}=\frac{2\pi}{0.20}=31.4 rad/s$

So, the wave equation (in meters) is

$z = 0.003 sin (6000y-31.4 t)$

(b) 0.094 m/s

For a transverse wave, the transverse speed is equal to the derivative of the displacement of the wave, so in this case:

$v_t = z' = -A \omega cos (ky-\omega t)$

So the maximum transverse wave occurs when the cosine term is equal to 1, therefore the maximum transverse speed must be

$v_{t}_{max} =\omega A$

where

$\omega = 31.4 rad/s\\A = 0.003 m$

Substituting,

$v_{t}_{max}=(31.4)(0.003)=0.094 m/s$

(c) 5.24 mm/s

The wave speed is given by

$v=f \lambda$

where

f is the frequency of the wave

$\lambda$ is the wavelength

The frequency can be found from the angular frequency:

$f=\frac{\omega}{2\pi}=\frac{31.4}{2\pi}=5 Hz$

While the wavelength can be found from the wave number:

$\lambda = \frac{2\pi}{k}=\frac{2\pi}{6000}=1.05\cdot 10^{-3} m$

Therefore, the wave speed is

$v=(5)(1.05\cdot 10^{-3} )=5.24 \cdot 10^{-3} m/s = 5.24 mm/s$

7 0

4 years ago

B) Smartphone, iPad, and tablet are also a kind of computer.

valentinak56 [21]

Answer:

Yes

Explanation:

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3 years ago

What type of pipe wrenches are designed for turning and holding where marring is not objectionable?

galina1969 [7]

The type of pipe wrenches which are designed to turn and hold where marring is not objectionable is known as the chain wrench.<span> It has two serrated which adjust and grip the pipe. </span>

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4 years ago