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3 years ago

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8. What is the weight in newtons of a 10 kg mass on the earth's surface?

1 answer:

iogann1982 [59]3 years ago

7 0

Weight = Mass times Acceleration due to gravity.

Weight = 10 kg times 9.8 m/s^2

Weight = 98 kg

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Name 2 ways that sound waves and electromagnetic waves are different. Describe specifically.

Vlad1618 [11]

Answer:Sound waves are longitudinal waves that is, are transmitted in the same direction of oscillation of the particles in the medium. Electromagnetic waves are transverse ie, the electric and magnetic fields, which are perpendicular to each other, oscillate perpendicularly to the direction of wave propagation.

Explanation:

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3 years ago

What is it plz help me!!

Darina [25.2K]

Answer:

second one

Explanation:

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3 years ago

Read 2 more answers

1. The string shown is 1.5 meters long and is vibrating as the first harmonic. The string vibrates up and down with 33 cycles in

svet-max [94.6K]

Answer:

Explanation:

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3 years ago

A soccer ball is released from rest at the top of a grassy incline. After 6.2 seconds, the ball travels 47 meters. One second la

alexandr1967 [171]

Answer:

(a) a = 2.44 m/s²

(b) s = 63.24 m

Explanation:

(a)

We will use the second equation of motion here:

$s = v_it+\frac{1}{2}at^2$

where,

s = distance covered = 47 m

vi = initial speed = 0 m/s

t = time taken = 6.2 s

a = acceleration = ?

Therefore,

$47\ m = (0\ m/s)(6.2\ s)+\frac{1}{2}a(6.2\ s)^2\\\\a = \frac{2(47\ m)}{(6.2\ s)^2}$

<u>a = 2.44 m/s²</u>

<u></u>

(b)

Now, we will again use the second equation of motion for the complete length of the inclined plane:

$s = v_it+\frac{1}{2}at^2$

where,

s = distance covered = ?

vi = initial speed = 0 m/s

t = time taken = 7.2 s

a = acceleration = 2.44 m/s²

Therefore,

$s = (0\ m/s)(6.2\ s)+\frac{1}{2}(2.44\ m/s^2)(7.2\ s)^2\\\\$

<u>s = 63.24 m</u>

6 0

3 years ago

A proton of mass m is at rest when it is suddenly struck head-on by an alpha particle (which consistsof 2 protons and 2 neutrons

antiseptic1488 [7]

Answer:

3/5 v

Explanation:

The computation of speed will the alpha particle have after the collision is shown below:-

In a perfectly elastic the kinetic energy and collision the momentum are considered.

The velocity of the particles defines the below equation:

$VA_f=(\frac{m_A-m_B}{m_A+m_B})VA_i+(\frac{2m_B}{m_A+m_B})VB_i$

As we know that

$VA_i=v$

$\\VB_i=0$

Here, we consider A is the alpha particle and B is the proton and now by the above values we can solve the equation which is below:-

$VA_f=(\frac{4m-m}{4m+m})v$

$\\VA_f=\frac{3m}{5m}v$

$\\VA_f=\frac{3}{5}v$

Therefore the correct answer is $\frac{3}{5}v$

7 0

3 years ago