Answer:
L_max= 0
Explanation:
The formula for magnitude of maximum orbital angular momentum is given by

l= orbital quantum number
l= n-1
n= shell number or principal quantum number
for n=1 , l=0
therefore, 
L_max= 0
K.E = 0.5 * m * v^2
= 0.5 * 80 * (1.5)^2
K.E = 90 joule
<span>when two hydrogen atoms approach each other the potential energy of the combination becomes lower and lower until it reaches a minimum value of -436 kl/mol at a distance of 75 pm</span>
0.9 is less than 1.0 by 0.1
so your answer is true
hope this helps
Answer: 4
Explanation: when you're solving velocity you should divide the two numbers so 16/4=4