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3 years ago

A single brick falls with acceleration g. The reason a double brick falls with the same acceleration is

Physics

2 answers:

rewona [7]3 years ago

6 0

EVERYTHING falls with the same acceleration near the earth's surface.

I thought about this for many years. I finally understood WHY, and here's the way I like to explain it:

-- It takes MORE FORCE to accelerate a larger mass, and LESS FORCE to accelerate a smaller mass.

-- But guess what ! Gravity exerts MORE FORCE on a larger mass, and LESS FORCE on a smaller mass.

So everything averages out, and the acceleration is always the same, no matter what's falling.

To say it just a little bit differently:

-- A larger mass NEEDS more force to accelerate, but it GETS more force from gravity.

-- A smaller mass NEEDS less force to accelerate, but it GETS less force from gravity.

So everything averages out, and the acceleration is always the same, no matter what's falling.

LekaFEV [45]3 years ago

5 0

The reason is because the force due to the acceleration from gravity is constant. It's the same as the typical "dropping a bowling ball and feather (with no air resistance) at the same time". Gravity acts on all object with the same acceleration regardless of physical properties.

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In an electrostatic field, path 1 between points A and B is twice as long as path 2. The electrostatic work done on a negatively

Elanso [62]

Answer:

W2 = W1

Explanation:

work is independent of the path taken between the points.

8 0

3 years ago

Briefly explain how an electric motor works.

NeTakaya

You put electricity<span> into it at one end and an </span>axle<span> (metal rod) rotates at the other end giving you the power to drive a machine of some kind.

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3 0

3 years ago

A 4-79 permalloy solenoid coil needs to produce a minimum inductance of 1.1 . If the maximum allowed current is 4 , how many tur

daser333 [38]

The related concept to solve this exercise is given in the expressions that the magnetic field has both as a function of the number of loops, current and length, as well as inductance and permeability. The first expression could be given as,

The magnetic field H is given as,

$H = \frac{nI}{l}$

Here,

n = Number of turns of the coil

I = Current that flows in the coil

l = Length of the coil

From the above equation, the number of turns of the coil is,

$n = \frac{Hl}{I}$

The magnetic field is again given by,

$H = \frac{B}{\mu_t}$

Where the minimum inductance produced by the solenoid coil is B.

We have to obtain n, that

$n = \dfrac{\frac{B}{\mu_t}l}{I}$

Replacing with our values we have that,

$n = \dfrac{\frac{1.1Wb/m^2 }{200000}(2m)}{4mA}$

$n = \dfrac{(\frac{1.1Wb/m^2 }{200000})(\frac{10^4 guass}{1Wb/m^2})(2m)}{4mA(\frac{10^{-3}A}{1mA})}$

$n = 27.5 \approx 28$

Therefore the number of turn required is 28Truns

4 0

3 years ago

A block with mass 0.5 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.2 m. W

lianna [129]

Answer:

So coefficient of kinetic friction will be equal to 0.4081

Explanation:

We have given mass of the block m = 0.5 kg

The spring is compressed by length x = 0.2 m

Spring constant of the sprig k = 100 N/m

Blocks moves a horizontal distance of s = 1 m

Work done in stretching the spring is equal to $W=\frac{1}{2}kx^2=\frac{1}{2}\times 100\times 0.2^2=2J$

This energy will be equal to kinetic energy of the block

And this kinetic energy must be equal to work done by the frictional force

So $\mu mg\times s=2$

$\mu\times 0.5\times 9.8\times 1=2$

$\mu =0.4081$

So coefficient of kinetic friction will be equal to 0.4081

5 0

3 years ago

The influence of blood vessel diameter on peripheral resistance is ________.

NeX [460]

Answer:

The influence of diameter of the blood vessel on peripheral resistance is significant because resistance is inversely proportional to the fourth power of the diameter.

Explanation:

The influence of diameter of the blood vessel on peripheral resistance is significant because the relation between the peripheral resistance and the diameter is given as, resistance is inversely proportional to the fourth power of the diameter. Thus, with small increase or decrease in the value of diameter, the peripheral resistance may vary by a significant amount.

6 0

3 years ago