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san4es73 [151]
3 years ago
8

A single brick falls with acceleration g. The reason a double brick falls with the same acceleration is

Physics
2 answers:
rewona [7]3 years ago
6 0

EVERYTHING falls with the same acceleration near the earth's surface.

I thought about this for many years.  I finally understood WHY, and here's the way I like to explain it:

-- It takes MORE FORCE to accelerate a larger mass, and LESS FORCE to accelerate a smaller mass.

-- But guess what !  Gravity exerts MORE FORCE on a larger mass, and LESS FORCE on a smaller mass.

So everything averages out, and the acceleration is always the same, no matter what's falling.

To say it just a little bit differently:

-- A larger mass NEEDS more force to accelerate, but it GETS more force from gravity.

-- A smaller mass NEEDS less force to accelerate, but it GETS less force from gravity.

So everything averages out, and the acceleration is always the same, no matter what's falling.

LekaFEV [45]3 years ago
5 0

The reason is because the force due to the acceleration from gravity is constant. It's the same as the typical "dropping a bowling ball and feather (with no air resistance) at the same time". Gravity acts on all object with the same acceleration regardless of physical properties.

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What is the largest planet in our galaxy
ludmilkaskok [199]
In our Solar System, Jupiter is the largest planet we have. it has the surface area of 23.71 billion mi^2. it beats all the other planets in both mass and volume.
4 0
2 years ago
For general projectile motion, the horizontal component of a projectile's velocity aSelect one:O a. continuously increases.O b.
liubo4ka [24]

ANSWER:

d. remains a non-zero constant.

STEP-BY-STEP EXPLANATION:

If we consider that there is no air resistance and that the horizontal component would be at x, the velocity remains a non-zero constant

3 0
10 months ago
Light with a frequency of 7.30 x 1014 hz lies in the violet region of the visible spectrum. What is the wavelength of this frequ
Leona [35]

From the theory we know that:

c = λ / T

f = 1 / T

Where:

c = 3.10^{8} / m   (the speed of light)

λ is the wavelengh (in meters)

T is the period (in seconds)

f is the frequency (in Hz)

We were told that:

f = 7.30 . 10^{14}

And we want to find out the value of λ.

c = λ / T  

c = λ . 1/T

Swaping 1/T = f

c = λ . f

λ = c / f

λ = 3 . 10^{8} /  7.30 . 10^{14}

λ = 4.12 10^{-7} m

Response: 4.12 10^{-7} m = 412 nm

:-)

6 0
3 years ago
What is the final speed?
EastWind [94]
U=6.9ms-¹
a=0.62ms-²
t=3.4s
V=?
using
v=u+at
v=6.9+(0.62×3.4)
v= 6.9+2.108
v=9.008ms-¹
6 0
2 years ago
A missle is fired horizontally with an initial velocity of 45 m/s from the top of a building 75 m high.
NARA [144]

The horizontal range of the missile is b) 176 m

Explanation:

The motion of the missile is a projectile motion, so it consists of two independent motions:  

- A uniform motion with constant velocity along the horizontal direction  

- A uniformly accelerated motion with constant acceleration (equal to the acceleration of gravity) in the vertical-downward direction  

To find the time of flight of the missile, we study the vertical motion. We can use the following suvat equation:

s=u_y t+\frac{1}{2}at^2

where:

s = 75 m is the vertical displacement of the missile (the height of the building)

u_y=0 is the initial vertical velocity  (the missile is thrown horizontally)

t is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find the time of flight:

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(75)}{9.8}}=3.91 s

This means that the missile takes 3.91 s to reach the ground.

Now we study the horizontal motion: the missile moves with a constant horizontal velocity of

v_x = 45 m/s

Therefore, the distance covered in a time t is

d=v_x t

and by substituting t = 3.91 s, we find the horizontal range of the missile:

d=(45)(3.91)=176 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

4 0
3 years ago
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