3 years ago

Pls help will give brainliest

Physics

1 answer:

max2010maxim [7]3 years ago

5 0

Explanation:

the correct answer is Option 5.√½gh.

hope this helps you.

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Can someone help me please it is number 7

motikmotik

D. The string vibrated because of resonance, which happened because the tuning fork and guitar string have same natural frequency.

4 0

4 years ago

If a 16 N net force makes an object accelerate at 4 m/s2, what is the mass of the object?

12345 [234]

Answer:

4 kg

Explanation:

Acceleration = 4 m/s^2

Force = 16 N

Force = mass * acceleration

mass = force / acceleration

mass = 16 / 4

mass = 4 kg

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3 years ago

A length of wire is cut into five equal pieces. if each piece has a resistance of 0.45 ω, what was the resistance of the origina

azamat

Calculation, add them. 0.85 x 5 = 4.25 Ω

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3 years ago

The period of a simple pendulum is 3.5 s. The length of the pendulum is doubled. What is the period T of the longer pendulum?

Rudik [331]

Answer:

Explanation:

T = 2π√(L/g)

If you increase L to 2L, the period is increased by a factor of √2

T = 3.5√2 ≈ 4.9 s

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3 years ago

Two satellites, A and B are in different circular orbits

jek_recluse [69]

Answer:

The ratio of the orbital time periods of A and B is $\frac{1}{2}$

Solution:

As per the question:

The orbit of the two satellites is circular

Also,

Orbital speed of A is 2 times the orbital speed of B

$v_{oA} = 2v_{oB}$ (1)

Now, we know that the orbital speed of a satellite for circular orbits is given by:

$v_{o} = \farc{2\piR}{T}$

where

R = Radius of the orbit

Now,

For satellite A:

$v_{oA} = \farc{2\piR}{T_{a}}$

Using eqn (1):

$2v_{oB} = \farc{2\piR}{T_{a}}$ (2)

For satellite B:

$v_{oB} = \farc{2\piR}{T_{b}}$ (3)

Now, comparing eqn (2) and eqn (3):

$\frac{T_{a}}{T_{b}} = \farc{1}{2}$

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3 years ago