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Naddik [55]
3 years ago
13

Why do sound waves move faster through the ground than through the air? a. Particles of matter are packed more loosely in the gr

ound than in the air. b. Particles of matter are packed more tightly in the ground than in the air. c. Air doesn’t contain any particles of matter to transmit sound waves. d. The elevation of the ground is lower than the elevation of the air space.
Physics
2 answers:
Vlad [161]3 years ago
7 0

The correct answer is

b. Particles of matter are packed more tightly in the ground than in the air.

Sound waves generally move faster in solids than liquids and gases. The reason is that sound waves are vibrations of the molecules of the medium: therefore, if the particles of the medium are closer together (as in solids), the vibrations can be transmitted faster, and the wave can travel faster. On the contrary, in gases the particles are spread apart, so the vibrations are not transmitted so easily (because there are less collisions between the particles) and the wave travels slower.

lbvjy [14]3 years ago
5 0
B. is it i just got done this in class like two weeks ago hope it helps

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The magnitude of each force is 208 N the force on the right is applied at an angle 36° and the mass of the block is 17 kg the co
djyliett [7]

Answer:

<em>11.06m/s²</em>

Explanation:

According to Newtons second law of motion

\sm F_x = ma_x\\F_m - F_f = ma_x\\mgsin \theta - \mu R mgcos \theta = ma_x\\

Given

Mass m = 17kg

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a is the acceleration

Substitute

208 - 0.148(17)(9.8)cos 36 = 17a

208 - 24.6568cos36 = 17a

208 - 19.9478 = 17a

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6 0
3 years ago
At what point does the external energy enter the system?
Phoenix [80]
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8 0
3 years ago
ONLINE CALCULATOR .A force of 187 pounds makes an angle of 73 degrees 36 ' with a second force. The resultant of the two forces
saul85 [17]

Answer:

The magnitudes of the second force is   Z = 129.9 N

The magnitudes of the  resultant force is   R = 256.047 N

Explanation:

From the question we are told that  

    The force is  F = 187 \ lb

     The angle made with second force \theta_o = 73 ^o 36' =  73 + \frac{36}{60}  =  73.6^o

     The angle between the resultant force and the first force \theta _1  = 29 ^o 1 ' = 29 + \frac{1}{60}  = 29.0167^o

For us to solve problem we are going to assume that

     The magnitude of the second force is  Z N

     The magnitude of the resultant force is R N

According to Sine rule

                \frac{F}{sin (\theta _o - \theta_1 }  = \frac{Z}{\theta _1}

Substituting values

             \frac{187}{sin(73.3 - 29.01667)} =\frac{Z}{sin (29.01667)}  

             267.82 =\frac{Z}{0.4851}  

              Z = 129.9 N

According to cosine rule

       R = \sqrt{F ^2 + Z^2 + 2(F) (Z) cos (\theta _o) }

Substituting values

     R = \sqrt{187^2 + 129.9 ^2  + 2 (187 ) (129.9) cos (73.6)}

     R = 256.047 N

 

3 0
3 years ago
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