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Naddik [55]
3 years ago
13

Why do sound waves move faster through the ground than through the air? a. Particles of matter are packed more loosely in the gr

ound than in the air. b. Particles of matter are packed more tightly in the ground than in the air. c. Air doesn’t contain any particles of matter to transmit sound waves. d. The elevation of the ground is lower than the elevation of the air space.
Physics
2 answers:
Vlad [161]3 years ago
7 0

The correct answer is

b. Particles of matter are packed more tightly in the ground than in the air.

Sound waves generally move faster in solids than liquids and gases. The reason is that sound waves are vibrations of the molecules of the medium: therefore, if the particles of the medium are closer together (as in solids), the vibrations can be transmitted faster, and the wave can travel faster. On the contrary, in gases the particles are spread apart, so the vibrations are not transmitted so easily (because there are less collisions between the particles) and the wave travels slower.

lbvjy [14]3 years ago
5 0
B. is it i just got done this in class like two weeks ago hope it helps

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A cell phone is released from the top with the speed of 10ms what is the speed 3s after?
sergeinik [125]

Answer:

30ms

Explanation:

you need to multiple the 10ms by 3s which gives you 30ms

6 0
3 years ago
Kenitic Energy (KE)<br> 1.doubled
astra-53 [7]

Answer:

mass

Explanation:

This energy of motion is what we call kinetic energy. ... In fact, kinetic energy is directly proportional to mass: if you double the mass, then you double the kinetic energy. Second, the faster something is moving, the greater the force it is capable of exerting and the greater energy it possesses.

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3 0
2 years ago
The plates of a spherical capacitor have radii 6.25 cm and 15.0 crn. The space between the two spheres is filled with a material
aleksklad [387]

Answer:

Capacitance is 0.572×10⁻¹⁰ Farad

Explanation:

Radius = R₁ = 6.25 cm = 6.25×10⁻² m

Radius = R₂ = 15 cm = 15×10⁻² m

Dielectric constant = k = 4.8

Electric constant = ε₀ = 8.854×10⁻¹² F/m

ε/ε₀=k

ε=kε₀

Capacitance\ (C)=\frac{4\pi k\epsilon_0 R_1\times R_2}{R_2-R_1}\\\Rightarrow C=\frac{4\pi 4.8\times 8.854\times 10^{-12}\times 15\times 10^{-2}\times 6.25\times 10^{-2}}{15\times 10^{-2}-6.25\times 10^{-2}}\\\Rightarrow C=0.572\times 10^{-10}\ Farad

∴ Capacitance is 0.572×10⁻¹⁰ Farad

3 0
3 years ago
Scientific notation of 86400
Mandarinka [93]
8.64×10^4

this is 86400 in scientific notation

3 0
3 years ago
Read 2 more answers
In a certain time period a coil of wire is rotated from one orientation to another with respect to a uniform 0.38-T magnetic fie
juin [17]
<h2>The emf produced is 7.2 V</h2>

Explanation:

When coil is placed in the magnetic field , the flux attached with it can be found by the relation . Flux Ф = the dot product of magnetic field and area of coil .

Thus Ф = B A cosθ

here B is magnetic field strength and A is the area of coil .

The angle θ is the angle between coil and field direction .

When coil rotates , the angle varies . By which the flux varies . The emf is produced in coil due to variation of flux . The relation for this is

The emf produced ξ = - \frac{d\phi}{dt} =  B A sinθ \frac{d\theta}{dt}

Now in the given problem

5 = 0.38 x A x \frac{d\theta}{dt}                            I

Now if the magnetic field is 0.55 T and all the other terms are same , the emf produced

ξ = 0.55 x A x \frac{d\theta}{dt}                              Ii

dividing II by I , we have

\frac{\xi}{5} = \frac{0.55}{0.38} = 1.45

or ξ = 7.2 V

6 0
3 years ago
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