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Tresset [83]
2 years ago
15

Oxygen difluoride is a hazardous, highly explosive gas used as a propellant. A sample of this compound weighing 0.432 grams is a

nalyzed. It contains .128 grams of oxygen. What is the percentage composition of oxygen and fluorine in this compound ? (Show work)
Chemistry
1 answer:
dimulka [17.4K]2 years ago
7 0

Answer:

Percentage composition of oxygen = 29.69%

Percentage composition of fluorine = 70.37

Explanation:

Given:

Mass of compound = 0.432 grams

Mass of oxygen = 0.128 grams

Find:

Percentage composition of oxygen

Percentage composition of fluorine

Computation:

Percentage composition of oxygen = [0.128/0.432]100

Percentage composition of oxygen = 29.69%

Percentage composition of fluorine = [(0.432 - 0.128)/0.432]100

Percentage composition of fluorine = 70.37

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strong enough to hold molecules relatively close together but not strong enough to keep molecules from moving past each other.

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2 years ago
If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density
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Answer:

The length of the wire = 352.66 feet.

Explanation:

A copper refinery produces a copper ingot weighing 150 lb. If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density of copper is 8.94 g/cm3. (Assume that the wire is a cylinder whose volume is V = πr2h, where r is the radius and h is its height or length.)

Step 1: Convert lb to kg

150 lb = 68.0389 kg

Step 2: Calculate volume of copper

Volume = mass / density

Volume = 68038.9 grams / 8.94 g/cm³

Volume = 7610.6 cm³ Cu

Step 3: Calculate length of wire

The diameter of the wire is 9.50 mm, so the radius is half of that (4.75 mm), or 0.475 cm.

The total "volume" of the wire is πr²h = (π)*(0.475 cm)²(h) = 0.708h = 7610 cm^3

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The length of the wire = 352.66 feet.

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