At temperature 298K, the value of k1/k2 will equal to 2.00
According to Arrhenius's equation
Sometimes the Arrhenius equation is written as k = Ae-, where k is the rate of the chemical reaction, A is a constant that varies depending on the chemicals involved, E is the activation energy, and R is the universal gas constant, and T is the temperature.
=
Given
Eₐ₂ = 69.8 × 10³ J/mol
Eₐ₁ = 45.3 × 10³ J/mol
R = 8.314J/kmol³
Now if the rate constant is equal means K1/K2 = 1 at T = 320 K
So if we put the values of K1/K2, Ea2,Ea1, T, and R into the formula
On solving
We get
A1/A2 = 1.001 × 10⁻⁴
Now when K1/K2 = 2
Then if we put the value of A1/A2, Ea1, Ea2, R, K1/K2 in the same equation,
On solving we get
T = 298 K
Hence, At temperature 298K k1/k2 will equal to 2.00
Learn more about Arrhenius's equation here brainly.com/question/26724488
#SPJ4