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cestrela7 [59]
2 years ago
6

Iron(III) oxide is formed when iron combines with oxygen in the air. How many grams of Fe2O3 are formed when 1.47 g of Fe reacts

completely with oxygen?
Chemistry
1 answer:
ozzi2 years ago
8 0

Answer:

2.10 g

Explanation:

Write the unbalanced reaction:

Fe + O₂ → Fe₂O₃

Balance it:

4Fe + 3O₂ → 2Fe₂O₃

Now use stoichiometry.  Convert mass of Fe to moles of Fe:

1.47 g Fe × (1 mol Fe / 55.8 g Fe) = 0.0263 mol Fe

Convert moles of Fe to moles of Fe₂O₃:

0.0263 mol Fe × (2 mol Fe₂O₃ / 4 mol Fe) = 0.0132 mol Fe₂O₃

Finally, convert moles of Fe₂O₃ to mass of Fe₂O₃:

0.0132 mol Fe₂O₃ × (159.7 g Fe₂O₃ / mol Fe₂O₃) = 2.10 g Fe₂O₃

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How far apart must two point charges of 75.0 nC (typical of static electricity) be to have a force of 1.00 N between them? (answ
Jet001 [13]

Answer:

7.12 mm

Explanation:

From coulomb's law,

F = kqq'/r².................... Equation 1

Where F = force, k = proportionality constant, q and q' = The two point charges, r = distance between the two charges.

Make r the subject of the equation,

r = √(kqq'/F).......................... Equation 2

Given: q = q' = 75.0 nC = 75×10⁻⁹ C, F = 1.00 N

Constant: k = 9.0×10⁹ Nm²/C².

Substitute into equation 2

r = √[ (75×10⁻⁹ )²9.0×10⁹/1]

r = 75×10⁻⁹.√(9.0×10⁹)

r = (75×10⁻⁹)(9.49×10⁴)

r = 711.75×10⁻⁵

r = 7.12×10⁻³ m

r = 7.12 mm

Hence the distance between the point charge = 7.12 mm

3 0
3 years ago
600.0 mL of air is at 20.0 Celsius. What is the volume of the same air at 60.0 Celsius
REY [17]

Answer:

0.682L or 682mL

Use Charles Law of V1/T1 = V2/T2

V1 = 0.6L

T1 = 293K

V2=?

T2= 333K

Explanation:

?

6 0
2 years ago
If the starting volume of a hot air balloon is 55,500 m3and the initial temperature is 21 °C, what is the temperature inside the
Dmitry_Shevchenko [17]

Answer:

T₂ = 392 K

Explanation:

Given that,

Initial volume of the hot air balloon, V₁ = 55500 m³

Initial temperature, T₁ = 21°C = 294 K

Final volume, V₂ = 74000 m³

We need to find the final temperature inside the balloon. The relation between the temperature and volume is given by charles law i.e.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where

T₂ is the final temperature

So,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{294\times 74000 }{55500 }\\\\T_2=392\ K

So, the new temperature is 392 K.

8 0
2 years ago
What is the systematic name of the following compound?
Ede4ka [16]

Answer: D. Potassium bromide

6 0
3 years ago
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Glad I could help, and good luck!
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