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3 years ago

Which of the following best demonstrates Newton's Third Law?

Physics

2 answers:

masya89 [10]3 years ago

6 0

It’s the third option

hjlf3 years ago

3 0

Answer:

when you walk your foot pushes down on the ground, while the ground pushes back on your foot

Explanation:

it was another brainly question, Goodluck :)

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When an electric stove element is hot enough, it gives off a dull red glow. When it cools to the point that it no longer glows,

DochEvi [55]

Answer:

It will have a longer wavelength

Explanation:

When an electric stove is hot and gives dull red glow. a part of the energy dissipated is emitted as visible light and part as infrared radiation in the form of heat. When the stove cools down, and no longer glows all the energy is now in the form of infrared radiation.In the electromagnetic spectrum infrared rays have a higher wavelength than visible light. Hence for the reason the radiation will have a higher wavelength since visible light is cut off.

4 0

3 years ago

A cylindrical blood vessel is partially blocked by the buildup of plaque. At one point, the plaque decreases the diameter of the

densk [106]

Answer:10.4 times of initial velocity

Explanation:

Given

Diameter reduced by 69 %

it approaches with velocity $v_0$

suppose its velocity is v during blocked passage

suppose d is the initial diameter and $d_2$ diameter is

$d_2=d(1-0.69)$

$d_2=0.31 d$

$A_2=\frac{\pi d_2^2}{4}$

As flow is constant

$Q_1=Q_2$

$d^2v_0=d_2^2v$

$v=10.40 v_0$

6 0

3 years ago

Which illustrates different states of a substance?

DanielleElmas [232]

Answer:

Ice and water vapor.

Explanation:

Ice is a solid state and water vapor is gas. Gas comes from water being heated. Plasma is also a fourth, less known, state of matter. I hope this helps. :)

6 0

3 years ago

Read 2 more answers

A 500 kg dragster accelerates from rest to a final speed of 100 m/s in 400 m (about a quarter of a mile) and encounters an avera

Fantom [35]

In order to accelerate the dragster at a speed $v_f = 100 m/s$ , its engine must do a work equal to the increase in kinetic energy of the dragster. Since it starts from rest, the initial kinetic energy is zero, so the work done by the engine to accelerate the dragster to 100 m/s is
$W= K_f - K_i = K_f = \frac{1}{2}mv_f^2=2.5 \cdot 10^6 J$

however, we must take into account also the fact that there is a frictional force doing work against the dragster, and the work done by the frictional force is:
$W_f = F_f d = -(1200 N)(400 m)= -4.8 \cdot 10^5 J$
and the sign is negative because the frictional force acts against the direction of motion of the dragster.

This means that the total work done by the dragster engine is equal to the work done to accelerate the dragster plus the energy lost because of the frictional force, which is $-W_f$ :
$W_t = W + (-W_f)=2.5 \cdot 10^6 J+4.8 \cdot 10^5 J=2.98 \cdot 10^6 J$

So, the power delivered by the engine is the total work divided by the time, t=7.30 s:
$P= \frac{W}{t}= \frac{2.98 \cdot 10^6 J}{7.30 s}=4.08 \cdot 10^6 W$

And since 1 horsepower is equal to 746 W, we can rewrite the power as
$P=4.08 \cdot 10^6 W \cdot \frac{1 hp}{746 W} =547 hp$

3 0

4 years ago

Read 2 more answers

A 6 kg bowling ball is accelerated at a rate of 2.3 m/s² down the lane. How much force was necessary to produce this acceleratio

ira [324]

According to Newton's 2nd law of motion:
F = m * a where F is the force applied in Newtons, m is the mass of the object in kg, and a is the acceleration of the object in m/ $s^{2}$ .
Therefore the force applied in this situation is simply:
F = 6 kg * 2.3 m/ $s^{2}$ = 13.8 N
Hope this helps!

6 0

3 years ago