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mr_godi [17]
3 years ago
12

At 2.5 seconds, the helicopter has a kinetic energy of 20J. What is its mechanical energy at that time?

Physics
1 answer:
Vinvika [58]3 years ago
3 0
The mechanical energy of an object is equivalent to the sum of its potential and kinetic energy. If the helicopter is grounded, then its mechanical energy will be 20 J. If it is in the air, then its potential energy will be calculated using:P.E = mghAnd then added to the kinetic energy to obtain mechanical energy.
 
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jenyasd209 [6]

The correct answer is C. Velocity is a vector and requires a direction.

Explanation:

In physics both speed and velocity are used to study the motion of a body; however, they are slightly different. In the case of speed, this describes the rate of change in position based on distance and time, because of this, speed is based on a magnitude or quantity. On the other hand, velocity is a vector because it does not only includes a change of position but the direction of motion usually based on a specific location reference.

Considering this, it can be concluded the difference between speed and velocity is that "velocity is a vector and requires a direction" because velocity includes both the distance and time (speed) along with the direction while speed focuses only on time and distance.

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3 years ago
You are playing a violin, where the fundamental frequency of one of the strings is 440 Hz, as you are standing in front of the o
Natalka [10]

Answer:

a)   L = 440 cm

Explanation:

In the open tube on one side and cowbell on the other, we have a maximum in the open part and a node in the closed part, therefore the resonance frequencies are

             λ₁ = 4L             fundamental

             λ₃ = 4L / 3       third harmonic

             λ₅ = 4L / 5       five harmonic

             

The violin string is a fixed cure in its two extracts, so both are nodes, their length from resonance wave are

              λ₁ = 2L                    fundamental

             λ₂ = 2L / 2              second harmonic

             λ₃ = 2L / 3              third harmonic

             λ₄= 2L / 4               fourth harmonic

They indicate that resonance occurs in the fourth harmonic, let's look for the frequency

              v =λ f

for the fundamental

              v = λ₀ f₀

              V = 2L f₀

for the fourth harmonica

              v = λ₄  f ’

              v = L / 2  f'

             2L f₀ = L / 2 f ’

             f ’= 4 f₀

             f ’= 4 440

             f ’= 1760 Hz

for this frequency it has the resonance with the tube

           f ’= 4L

           L = f ’/ 4

           L = 1760/4

           L = 440 cm

b) let's find the frequency of the next harmonic in the tube

             λ₃ = 4L / 3

             λ₃ = 4 400/3

             λ₃ = 586.6 cm

            v = λf

            f = v / λlam₃

            f₃3 = 340 / 586.6

            f3 = 0.579

as the minimum frequency on the violin is 440 Beam there is no way to reach this value, therefore there are no higher resonances

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                            Wavelength  =  (speed) / (frequency)
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